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3 years ago

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Mathematics

2 answers:

qaws [65]3 years ago

6 0

KE = 1/2(m * v^2)

KE = 1/2(1350 * 12^2)
KE = 1/2(1350 * 144)
KE = 1/2(194,400)
KE = 97,200 Joules

timofeeve [1]3 years ago

6 0

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:

m (mass) = 1350 kg

v (velocity) = 12 m/s

KE (kinetic Energy) = ? (in Joule)

Formula to calculate kinetic energy:

$\boxed{KE = \dfrac{1}{2} *m*v^2}$

Solving:

$KE = \dfrac{1}{2} *m*v^2$

$KE = \dfrac{1}{2} *1350*12^2$

$KE = \dfrac{1}{2} *1350*144$

$KE = \dfrac{194400}{2}$

$\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}$

_______________________

$\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

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Answer:

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Step-by-step explanation:

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We compute the next iterations in MATLAB (see attachment)

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The average change of droplet radius with time is:

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