How do you eliminate the parameter theta to find a Cartesian equation of the curve: x=sin(1/2 theta), y=cos(1/2 theta), 0 is les s than or equal to theta and theta is less than or equal to 4pi
1 answer:
The answer to the problem is as follows: x = sin(t/2) <span>y = cos(t/2) </span> <span>Square both equations and add to eliminate the parameter t: </span> <span>x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 </span> <span>The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.</span>
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Answer:
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Step-by-step explanation:
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15 shirts.
Step-by-step explanation:
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x = 240/16 = 15
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