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oksian1 [2.3K]
2 years ago
15

A child throws a ball with a speed of 5 feet per second at an angle of 73 degrees with the horizontal. Express the vector descri

bed in terms of i and j.
Mathematics
1 answer:
maxonik [38]2 years ago
3 0

Answer:

  v = 5cos(73°)i +5sin(73°)j

Step-by-step explanation:

The components of the velocity vector are ...

  horizontal (i direction): 5·cos(73°)

  vertical (j direction): 5·sin(73°)

Then the velocity vector is the sum of these component vectors:

  v = 5cos(73°)i +5sin(73°)j

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A square has diagonal length 9m. What is the side length of the square, to the nearest centimeter?
bazaltina [42]
636cm. 

This can be found with the Pythagorean Theorem which will give you a side length of 4.5\sqrt{2}meters, which rounds to roughly 636cm. 
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2 years ago
Maria puts $2,500.00 in her money market account earning 8% interest annually. How much interest and how much money would she ha
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The correct answer: total interest = $1,784.56 and she would have $4,284.56 after 7 years
7 0
2 years ago
What is the product? (-3s+2t)(4s-t)​
Step2247 [10]

Answer:

−12s2+11st−2t2

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST& 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
2 years ago
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A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
2 years ago
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