The answer is 2 and over it is 3
Answer:
28. 120 degrees
29. 30 degrees
30. 56 degrees & 124 degrees
31. 72 degrees, 108 degrees, and 18 degrees
Step-by-step explanation:
We assign variable x for the answer we are looking for (28-29).
28.
Supplement means x + y = 180 degrees. We also know x = 2y. Substitution gives us 3y = 180 degrees, so y = 60 degrees and x = 120 degrees.
29.
Complement means x + y = 90 degrees. We are given 2x = y. Substitution brings us 3x = 90 degrees, x = 30 degrees.
30.
Supplement means x + y = 180 degrees. We are told that y = 2x + 12, so we substitute. This gives 3x + 12 = 180 degrees, x = 56 degrees. Substituting that back into the equation for y, we get 124 degrees.
31.
Supplement means x + y = 180 degrees. Complement means x + z = 90 degrees. Using our given info, we know y = 6z. We can substitute that in to get x + 6z = 180. Subtracting our second and third equations, we get 5z = 90, z = 18 degrees. Therefore, x = 72 degrees, y = 108 degrees.
<u>answer:</u> 
<u>work:</u>
| subtract 13.50 and move it over
| divide by 7/2
| final answer
Answer:
![[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}](https://tex.z-dn.net/?f=%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D%5E%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
![\frac{3}{2} [ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%20%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
ln(m/n)= lnm - ln(n)
![\frac{3}{2}[ln x(x^2 + 1) - ln(x + 1)]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20x%28x%5E2%20%2B%201%29%20-%20ln%28x%20%2B%201%29%5D)
![\frac{3}{2}[ln \frac{x(x^2 + 1)}{(x + 1)}]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Bln%20%5Cfrac%7Bx%28x%5E2%20%2B%201%29%7D%7B%28x%20%2B%201%29%7D%5D)
3/2 is before ln. so we move the fraction 3/2 to the exponent
as per log property we move the fraction to the exponent
