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3 years ago

1/3(3+2x)−1=10 PLEASE HURRY I NEED It IN LIKE 2 MINUTES

Mathematics

2 answers:

amid [387]3 years ago

4 0

Answer:

x = 15

I believe this is correct

Sholpan [36]3 years ago

3 0

Answer:

x=15

Step-by-step explanation:

crown plz

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jane and jill were simplifying the expression (2x2+x) +2(-x2+×) and obtained different answers . who is right and why?

Romashka [77]

Answer: who ever arrives at the answer x=0/3 =0 is correct

Step-by-step explanation:

Even though I need supporting details from the individual answers of Jane and Jill to pass my own judgment.

Given the expression

(2x²+x) +2(-x²+×)=0

Let's us open the bracket

2x²+x-2x²+2x=0

Collecting like terms

2x²-2x²+x+2x=0

3x=0

x=0/3

x=0

4 0

3 years ago

A total of 517 tickets were sold for the school play. They were either adult tickets or student tickets. There were 67 more stud

victus00 [196]

Answer:

My guess is 450.

Step-by-step explanation:

7 0

4 years ago

Please help me answer this!!!

Ronch [10]

No srry if I wrong .......

3 0

3 years ago

PLEASE HELPPP kahsjahsjad I need help

Klio2033 [76]

Answer:

$166\frac{2}{3} *x=y$

Step-by-step explanation:

$\frac{500}{3} =166\frac{2}{3}$

Therefore, $166\frac{2}{3} *x=y$

7 0

2 years ago

Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =

DanielleElmas [232]

Answer:

$c = 5$

Step-by-step explanation:

Given

$f(c) = M$

$f(x) = x^2 - x + 1$

$Interval: [1,8]$

$M = 21$

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

$f(x) = x^2 - x + 1$

$f(1) = 1^2 - 1 + 1$

$f(1) = 1$

$f(x) = 8^2 - 8 + 1$

$f(x) = 57$

$1 \le M \le 57$

$1 \le 21 \le 57$

M is within range.

Solving further:

We have:

$f(c) = f(x) = M$

$f(x) = 21$

Substitute 21 for f(x) in $f(x) = x^2 - x + 1$

$21 = x^2 - x + 1$

Express as quadratic function

$x^2 - x + 1 - 21 = 0$

$x^2 - x - 20 = 0$

Expand

$x^2 + 4x - 5x - 20$

$x(x+4)-5(x+4)=0$

$(x - 5)(x+4) = 0$

$x - 5 = 0$ or $x + 4= 0$

$x = 5$ or $x = -4$

The value of $x = -4$ is outside the $Interval: [1,8]$

So:

$x = 5$

$f(c) = f(x) = M$

$f(c) = f(5) = 21$

By comparison:

$c = 5$

4 0

3 years ago