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DochEvi [55]
3 years ago
5

A landscaper mowed 2.25 yards in 1.5 hours. How much did she mow in one hour?

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

The amount that the landscaper mowed in one hour would be 1.5 yards.

Step-by-step explanation:


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What does 2(n-3)=4n+1 equal
Liono4ka [1.6K]

Answer:

n=4/-3

Step-by-step explanation:

2n-3 = 5n+1

2n-5n = 1+3

-3n = 4

n =4/-3

n=-4/3

6 0
3 years ago
Read 2 more answers
URGENT!!!! Which of the following statements is not true?(1 point) A.) For a complex number written in the form a+bi, the value
baherus [9]

Answer:

The correct option is;

Non of the above

Step-by-step explanation:

Option A is correct when a + b·i is a complex number, the real part = a and the imaginary part = b

Option B.) For the complex number,  a + b·i, a and b are real number

Option C) When a number, a + b·i is a complex number, then b ≠ 0

Option D) Whereby real numbers are numbers of the form  a + b·i, where b = 0, therefore, a real number is a complex number with the imaginary part = 0 and every real number is a complex number.

7 0
3 years ago
Please help me with these four questions
Paraphin [41]

Answer:

23) 8

24)58

25)im guessing theyre both 90

Step-by-step explanation:

23)if ac=23 then 15-23=x

24) since it's a 90 degree angle the 32+x=90

and 90-32=58

7 0
3 years ago
Find the lateral area of the cylinder.<br><br>Give your answer in the terms of pi.
Wewaii [24]
Hi there! 

The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. (two times pi times radius times height) Using this formula, we can plug in the values and solve for the lateral area.

Plugging in the values: LA = 2 x pi x 7 x 9
Simplifying: LA = 2pi x 63
LA = 126pi yd^2

ANSWER:
The 4th option - 126pi yd^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
6 0
3 years ago
Ads Galore makes posters with standard dimensions of inches by 11 inches as shown.
larisa [96]
Poster standard dimension: 8.5 inches by 11 inches
Both length and width of the poster may vary 1/20%
∴ length and width may vary 1/20 % = 0.05% = 0.0005

∵ Area  = Width * Length
∴ Area = 8.5 * 11 = 93.5 in²

Smallest acceptable area for one poster:

Width: 8.5 * (1 - 0.0005) = 8.49575 in.
Length: 11 * (1 - 0.0005) = 10.9945 in.

∴ The smallest area = 8.49575 * 10.9945 = 93.4065 ≈ 93.407 in².






4 0
4 years ago
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