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Artyom0805 [142]
3 years ago
15

2x - 1 = 0 is a quadratic equation. True False

Mathematics
2 answers:
harina [27]3 years ago
6 0
I believe the answer is false

Hope this helps
alukav5142 [94]3 years ago
5 0
The answer is false.  Hope this helps.
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Which of the following expressions is equivalent to 4^-3?<br><br> ​
-BARSIC- [3]

Answer:

x(12y+4)

Step-by-step explanation:

6 0
2 years ago
Prove algebraically what type of function this is (even, odd, or neither).<br>f(x) = x^6 – x^4​
Savatey [412]

Let's see.

We have function f(x)=x^6-x^4. We have to determine if the function is even or odd or neither.

We can find this out in many ways but the assignment specifically asks to prove this algebraically.

Function is even if f(x)=f(-x), so, x^6-x^4=(-x)^6-(-x)^4

Which is true since negative raised to an even power is positive to that same number.

Similarly, function is odd if f(x)=-f(-x), that is,

x^6-x^4\neq-((-x)^6-(-x)^4).

So we have prooved that function f(x) is an even function not an odd function and therefore also not neither.

Hope this helps.

3 0
3 years ago
Can you answer this problem?
Rasek [7]
When there is a negative in squre root, it means imaginary number come in. 'i' is usually the varible used to identify imaginary numbers.
First remove the negative from the square root and find the square root of 4, which is 2. Then add i to 2. 2i

Now solve for the positive then negative.

-2 + 2i
----------- = -1 + 1i
2

-2 - 2i
----------- = -1 - 1i
2

Both -1 + 1i and -1 - 1i are the answers.
4 0
3 years ago
Katrina has two photos she wants to split them into half and put them into equal groups how many groups for Katrina have to make
olya-2409 [2.1K]
Katrina has to make 2 groups with two pieces in each group.

3 0
3 years ago
Read 2 more answers
Can someone help me with this physics equation please I am really in need of help
e-lub [12.9K]

Answer:

The current is approximately 8.571 Amps

Step-by-step explanation:

You are supposed to use Ohm's Law for this problem.

Recall that Ohm's Law gives you the relationship between voltage applied (V), resistance (R) and current (I):  

V=I\,*\,R

If the units of resistance are ohms, and the voltage is in volts, the current will be given in Amps (amperes). Then solving for the current (I) in the above equation:

I=\frac{V}{R} \\I=\frac{120}{14} \\I=8.571\,\,Amps

3 0
3 years ago
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