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frutty [35]
3 years ago
14

Please help i put 15 points for this

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

The first & the third are true.

Step-by-step explanation:

If you put the equation on the calculator, you'll get that x=1 then, the equation divides by (x-1) and has a remainder =0 & (x-1) is a factor of the equation since it gives a remainder=0

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What strategy would use to divide 36 by 6 explain why you chose that strategy
wel
I would pick long division because you regroup and better understand
6 0
3 years ago
Read 2 more answers
A photo is 15 centimeters high and 9 centimeters wide. Mikael wants to proportionately shrink it so its height is 6 centimeters
gtnhenbr [62]

Answer:

6:3.6

Step-by-step explanation:

The hight of the photo=15

so,15=6

15 :- 2.5=6

9 divided by 2.6= 3.6

therefour, the answer will be 6:3.6

8 0
3 years ago
Calculate a critical z-score for a left-tailed, right-tailed, or two-tailed test.
muminat

Answer:

a. Z = -1.175.

b. Z = 1.34.

c. |Z| = 2.054.

d. |Z| = 1.28.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. The critical z-score for a left-tailed test at a 12% significance level

Left-tailed test: The region of interest is the 12th percentile or below.

Thus, the critical z-score is Z with a p-value of 0.12, so Z = -1.175.

b. The critical z-score for a right-tailed test at a 9% significance level

Right-tailed test: The region of interest is the 100 - 9 = 91th percentile and above.

Thus, the critical z-score is Z with a p-value of 0.91, so Z = 1.34.

c. The critical z-score for a two-sided test at a 4% significance level is 1.75.

Two-tailed test: The region of interest is between the 4/2 = 2th percentile and the 100 - (4/2) = 98th percentile.

Thus, the critical z-score is |Z| with a p-value of 0.02 or 0.98, so |Z| = 2.054.

d. The critical z-score for a two-sided test at a 20% significance level is 0.85.

Region of interest is between the 20/2 = 10th percentile and the 100 - (20/2) = 90th percentile.

Thus, the critical z-score is |Z| with a p-value of 0.1 or 0.9, so |Z| = 1.28.

4 0
3 years ago
If f(x)=6x-15 and f(a)=30, what is the value of a?<br> Please help
mariarad [96]

Answer:

a=7.5

Step-by-step explanation:

Given the function f(x)=6x-15 and the output 30 when x=a, we can write the equation:

6a-15=30

6a=45

a=7.5

We can insert the value of a into the function to verify the output equals 30:

f(a) = 6a-15

= 6(7.5)-15

=30

∴ We have verified that a=7.5

Hope this helps :)

7 0
3 years ago
What is the purpose of calculating a confidence interval? Multiple Choice To provide a range of values that has a certain large
Nadusha1986 [10]

Answer:

To provide a range of values that, with a certain measure of confidence, contains the population parameter of interest.  

To provide a range of values that has a certain large probability of containing the population parameter of interest.

Step-by-step explanation:

For estimating a parameter value, it is important to know the statement or degree of confidence that the interval contains the parameter value along with knowing the point estimate and the amount of possible error in the point estimate (which is the interval likely to contain the parameter value).Thus , an interval estimate of a population parameter is the confidence interval with a statement of confidence that the interval contains the parameter value. The confidence interval is a range of values around the statistic that are believed to contain, with a certain probability (say 99%) the true value of that statistic or the population value.

8 0
4 years ago
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