Let the three consecutive integers be x, x+1 and x+2.
According to the question, x+x+1+x+2=51
=>3x+3=51
=>3x+3-3=51-3
=>3x=48
=>x=16
Hence, first integer = 16,
second integer = 16 + 1 = 17 and
third integer = 16 + 2 = 18.
Solution :
= 0.0836
P(B)= P(coin chosen and 4 heads in 10 trails) + P(coin chosen and 4 heads in 10 trail) + P(coin chosen and 4 heads in 10 trail)
P(A|B) =
When rounding, only look at the number to the immediate right of the place you are rounding to. In this example that would be the 4. If the number is 5 or more, round up, if it is 4 or less, round down.
Therefore 234.6 rounds to 230
Final answer:
230
Answer:
d. none of these
Step-by-step explanation: