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daser333 [38]
3 years ago
13

The product of 11/13 and 4 is:

Mathematics
2 answers:
kotegsom [21]3 years ago
5 0

Answer:

\frac{11}{13}  \times 4 \\  =  \frac{44}{13}  =3 5/13\\ thank \: you

kirza4 [7]3 years ago
4 0

Answer:

11/13 x 4 = 3 5/13

Step-by-step explanation:

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) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th
ArbitrLikvidat [17]

Answer:

28 ways

Step-by-step explanation:

After placing 1 ball in each of the seven bins, there are two balls left.

If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).

If we place each of the remaining balls in a different bin, the number of ways to place the balls is:

n_2=\frac{7!}{(7-2)!2!}=7*3=21

The total number of ways to distribute those balls is 21 + 7 = 28 ways.

3 0
3 years ago
Help please immediately
Vika [28.1K]

Answer:

c

Step-by-step explanation:yes

7 0
3 years ago
Read 2 more answers
PLEASE HELP ITS DUE SOON!!!!
Anvisha [2.4K]
Heberto could go 14 blocks East and 14 blocks south, so the last answer
3 0
2 years ago
While taking a ride in a hot-air balloon in Napa Valley, Francisco wonders how high he is. To find out, he chooses a landmark th
mihalych1998 [28]

 

The solution would be like this for this specific problem:

sin 54 degrees = Height/718.0624

Height = (sin 54 degrees)(718.0624) = 580.9 ft

So the height of the balloon is 580.9 ft. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
3 years ago
Read 2 more answers
I need help with this question please
Elza [17]

The changes in Z would be = 6.1× 10^-4.

<h3>Calculation of the unknown value</h3>

Z = Sin (x³ +y³)

Where X = 0.3

y = 0.2

Z= Sin ( 0.3³ + 0.2³)

Z= Sin ( 0.027 + 0.008)

Z= Sin ( 0.035)

Z= 6.1× 10^-4

Therefore, the changes in Z would be = 6.1× 10^-4.

Learn more about multiplication here:

brainly.com/question/10873737

#SPJ1

5 0
1 year ago
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