HELP!!! Completing the plot

Clare has a recipe for yellow cake. She uses 913 cups of flour to make 4 cakes. Noah will follow the same recipe. He will make c

sergejj [24]

Answer:

(C)c= $\frac{3}{7}$ f

Step-by-step explanation:

Clare uses $9\frac{1}{3}$ cups of flour to make 4 cakes.

It means she uses 1 cup of flour to make $4\div9\frac{1}{3}$ cakes.

Let us simplify that expression first for future use.

$4\div9\frac{1}{3}=4\div\frac{28}{3} =4 X \frac{3}{28} =\frac{3}{7}$

Therefore, Clare uses 1 cup of flour to make $\frac{3}{7}$ cakes.

If Noah follows the same recipe,

He uses f cups of flour to make c cakes

Using Ratio Method

→ Name : Cup : Cake

→ Clare : 1 : $\frac{3}{7}$

→ Noah : f : c

By using cross multiplication

c X 1 = $\frac{3}{7}$ f

c= $\frac{3}{7}$ f

The equation c= $\frac{3}{7}$ f represents the relationship between c and f

8 0

4 years ago

A cylinder had a diameter of 17 cm and a height of 11 cm. ehat is the volume of the cylinder

tester [92]

Answer:

2496.78

Step-by-step explanation:

7 0

3 years ago

**PLEASE HURRY**

Mariana [72]

Answer:

////

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

Please answer and no explanation needed

rewona [7]

Wait isn’t it 30 or am I reading it wrong?

3 0

3 years ago