Question

What is the measure of angle J in the triangle below? A. 99 B. 42 C. 9 D. 48

Answer 1

For this use the law of sines:
$\sin( \alpha ) \div a = \sin( \beta ) \div b \\ \sin( \alpha ) \div 11 = \sin(103) \div 16$
$\frac{ \sin( \alpha ) }{11} = \frac{0.97}{16}$
cross-multiply:
16×sin (J) = 11×0.97
sin(J) = 10.72/16
sin(J) = 0.67
hit the "arcsin" button on your calculator:
${ \sin}^{ - 1} (0.67) = 42.06 = 42.1 \: deg$
therefore answer B. 42 is the correct answer!!