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<h3> D. (x - 3)² = 17</h3>Step-by-step explanation:
A statement which correctly compares the two functions on the given interval [-1, 2] is: C. Both functions are increasing, but function g increases at a faster average rate.
<h3>How to compares the two functions?</h3>First of all, we would determine the values of function g(x) on the given interval [-1, 2] as follows:
g(x) = -18(⅓)^x + 2
At x = -1, we have:
g(-1) = -18(⅓)^(-1) + 2
g(-1) = -52.
At x = 0, we have:
g(0) = -18(⅓)^(0) + 2
g(0) = -16.
At x = 1, we have:
g(1) = -18(⅓)^(1) + 2
g(1) = -4.
At x = 2, we have:
g(2) = -18(⅓)^(0) + 2
g(2) = 0.
By critically observing the values of each functions, we can logically deduce that both functions are increasing but function g(x) increases at a faster average rate because it started with a lower value and ended with a higher value.
Read more on functions here: brainly.com/question/23575055
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