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2 years ago

13

Help please work with answer

1 answer:

Basile [38]2 years ago

3 0

All you have to do is take the size for every cereal, divide it with its price and you should get your answer as cents. then compare them all and see which one has the lowest price.

* don't forgot to put place holders and add a decimal.

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Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Quantity of Flour Price

mylen [45]

I think it’s D $0.53

3 0

2 years ago

13°38'35" to decimal degrees

babymother [125]

divide 35 by 3600

divide 38 by 60

add them together

35/3600 = 0.009722

38/60=0.6333

0.6333+0.009722 = 0.64305

so 13.64305 degrees. round answer as necssary

4 0

3 years ago

Read 2 more answers

What slope does a horizontal line have?

ioda

Answer:

Step-by-step explanation:

Horizontal

5 0

3 years ago

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What should you do to get both numeric terms on the right side of the equation?

Mariulka [41]

Answer:

you should take the numeric value _16 to right side.

6 0

2 years ago

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