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3 years ago

9

A bag contains 5 red, 5 blue, 4 green, and 2 yellow marbles. Find the probability of randomly choosing: a green then yellow (ind

ependent)
a.3/8
b.1/16
c.1/30
d.1/36

2 answers:

Snowcat [4.5K]3 years ago

6 0

Answer:

1/16

Step-by-step explanation:

you need to add it to have a correct answer

Nata [24]3 years ago

5 0

1/16 is the correct answer

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In decimal form, to the nearest tenth, what is the probability that a randomly selected Riverside High School student is in twel

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We have that the total students there are 500. The 12-graders there are 200. Probability is defined as the ratio of positive outcomes of an event, over all the possible outcomes. Suppose we pick student randomly. Then, there are 200 positive outcomes (positive outcome: we pick a student in 12th grade) and there are totally 500 outcomes (we can pick 500 students in total from Riverside High School). This ratio gives: $P= \frac{200}{500} =0.4$ . The requested probability is 0.40

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Solving two step equations

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2 years ago

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The question is: "Without actually graphing, describe how the graph of y = ( -2^(x+17) ) - 4.3 is related to the graph of y = 2^

mojhsa [17]

Answer:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

Step-by-step explanation:

When functions are transformed there are a few simple rules:

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Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).
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Multiplying the function by a number greater than 1 stretches it away from the x-axis.
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The graph of $(-2^{x+17}) -4.3$ compares to $2^x$ in the following ways:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

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3 years ago

Can someone help me calculate the area of this object?

nekit [7.7K]

Answer: 272.9 cm^2

How to:

25 * 8 = 200

9 * 8.1 = 72.9

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2 years ago

Match its group with its percentage or mean Using

krok68 [10]

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0

2 years ago