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Diano4ka-milaya [45]
2 years ago
14

The two cylinders pictured at the right are congruent Haw

Mathematics
1 answer:
leonid [27]2 years ago
8 0

The volume of the larger cone is equal to the total volume of the two smaller cones

<h3>How to compare both cones?</h3>

From the question, we have two equal cylinders.

This means that the cylinders have equal volume.

From the complete question, a large cone is placed in one of the cylinders, while two small cones are placed in the other.

Since the cylinders have equal volumes, then the volume of the large cone equals the sum of the volumes of the smaller cones.

Hence, the volume of the larger cone is equal to the total volume of the two smaller cones

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

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Vanyuwa [196]

Answer:

a + 20 = 7*12 (multiplied both sides by 12)

a + 20 = 84 (calculated 7*12)

a = 84 - 20 (subtracted 20 on both sides)

a = 64 (calculated 84-20)

4 0
3 years ago
Ve the equation. 3c + 1 = c +1​
yKpoI14uk [10]
Subtract C in both sides:
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3 years ago
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lubasha [3.4K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Please help!! thank you.
Zina [86]

(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20

=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20

=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



5 0
3 years ago
Solve each equation using the Quadra<br>1. 4x2 +1 1x - 20=0<br>​
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Answer:

x= 12/11

Step-by-step explanation:

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3 years ago
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