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2 years ago

The two cylinders pictured at the right are congruent Haw

Mathematics

1 answer:

leonid [27]2 years ago

8 0

The volume of the larger cone is equal to the total volume of the two smaller cones

<h3>How to compare both cones?</h3>

From the question, we have two equal cylinders.

This means that the cylinders have equal volume.

From the complete question, a large cone is placed in one of the cylinders, while two small cones are placed in the other.

Since the cylinders have equal volumes, then the volume of the large cone equals the sum of the volumes of the smaller cones.

Hence, the volume of the larger cone is equal to the total volume of the two smaller cones

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10x-5y=25 solve for y

Pavlova-9 [17]

<span>10x-5y=25 solve for y
so
10x - 5y = 25
5y = 10x - 25
y = 2x - 5

hope it helps</span>

8 0

3 years ago

Hii can someone help with this pls :)

BlackZzzverrR [31]

Answer:

$R(x,y) = (0.8,-1.2)$

Step-by-step explanation:

The coordinates of QS are:

$Q(x_1,y_1) = (-2,-6)$

$S(x_2,y_2) = (5,6)$

The ratio is represented as:

$R_{m:n} = 2:3$

Required

Find the coordinates of R

The coordinates of R is calculated by:

$R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})$

Substitute values for m, n, x's and y's

$R(x,y) = (\frac{2 * 5 + 3 * -2}{2+3},\frac{2*6 + 3*-6}{2+3})$

$R(x,y) = (\frac{4}{5},\frac{-6}{5})$

$R(x,y) = (0.8,-1.2)$

<em>None of the options is correct</em>

6 0

2 years ago

A cone with diameter 20 cm and a height of 20 cm. Find the volume of the cone rounded to the nearest tenth.

zhuklara [117]

Answer:

2094.4 cm³

Step-by-step explanation:

The volume of a cone =πr²h/3

Where

r = radius = Diameter/2

Diameter = 20cm, radius = 20cm/2 = 10cm

Height = 20cm

Volume of a cone = π × 10² × 20/3

Volume of a cone = 2094.3951 cm³

Approximately to the nearest tenth = 2094.4 cm³

Therefore , the volume of a cone = 2094.4 cm³

8 0

3 years ago

Law of cosines: a2 = b2 + c2 – 2bccos(A) What is the value of n to the nearest whole number? 18 22 29 41

nalin [4]

We know that
applying the law of cosines
a² = b²+ c²<span> – 2*b*c*cos(A)
</span>
in this problem
a=?
b=20
c=9
A=90°
so
a² = b²+ c² – 2*b*c*cos(A)
but
cos (A)=0
a² = b²+ c²-----> 20²+9²----> a²=400+81----> a²=481-----> a=√481
a=21.93-----> a=22

the answer is
22

4 0

3 years ago

Read 2 more answers

3^sqrt -64w^12<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20-%2064w%5E%7B12%7D%7D%20" id="TexFormula1" title=" \s

Agata [3.3K]

-64=(-4)³, w^12=(w^4)³
the result is -4w^4

7 0

2 years ago