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2 years ago

The two cylinders pictured at the right are congruent Haw

Mathematics

1 answer:

leonid [27]2 years ago

8 0

The volume of the larger cone is equal to the total volume of the two smaller cones

<h3>How to compare both cones?</h3>

From the question, we have two equal cylinders.

This means that the cylinders have equal volume.

From the complete question, a large cone is placed in one of the cylinders, while two small cones are placed in the other.

Since the cylinders have equal volumes, then the volume of the large cone equals the sum of the volumes of the smaller cones.

Hence, the volume of the larger cone is equal to the total volume of the two smaller cones

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Help? mathhhhhhhhhhhhhhhhhhhhhhhhhhhh

Vanyuwa [196]

Answer:

a + 20 = 7*12 (multiplied both sides by 12)

a + 20 = 84 (calculated 7*12)

a = 84 - 20 (subtracted 20 on both sides)

a = 64 (calculated 84-20)

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3 years ago

Ve the equation. 3c + 1 = c +1

yKpoI14uk [10]

Subtract C in both sides:
2c + 1 = 1

Subtract 1 on both sides
2c = 0

The solution is:
x = 0

Hope this helped

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3 years ago

What do you do when ur bathtub wont work

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Answer:

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Step-by-step explanation:

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3 years ago

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Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

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3 years ago

Solve each equation using the Quadra<br>1. 4x2 +1 1x - 20=0<br>

Tatiana [17]

Answer:

x= 12/11

Step-by-step explanation:

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3 years ago

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