Answer:
5, 3
Step-by-step explanation:
What are you trying to solve for?
the perimeter of the field is 442
width=w
the length of the field is 9 yards less than quadruple W
L=4x - 9
the perimeter is P=2L+2W
you can plug in the values
P= 2(4w-9) + 2W
plug in 442 for P
442= 2(4w- 9) + 2W
442= 8w - 36 + 2W
478 =8w + 2W
478= 10W
47.8 is your answer!!!
The problem is asking for the height of the fluid using the following information:
Volume of fluid
=
V
=
36
π
cm
3
Radius of new cylinder
=
r
=
3
cm
To start the solution, solve for the height
h
in the formula for the volume of a cylinder:
V
=
π
r
2
h
π
r
2
h
π
r
2
=
V
π
r
2
h
=
V
π
r
2
V =π
r
2
h
π
r
2
h
π
r
2
=
V
π
r
2
h =
V
π
r
2
Substituting the values of the volume and the radius, the height of the fluid is:
h
=
V
π
r
2
=
36
π
cm
3
(
3
cm
)
2
=
(
4
)
(
9
)
π
cm
3
(
9
)
cm
2
=
4
π
cm
=
12.5663706144
≈
12.6
cm
h =
V
π
r
2
=
36
π
cm
3
(
3
cm
)
2
=
(
4
)
(
9
)
π
cm
3
(
9
)
cm
2
=4π cm =12.5663706144≈12.6 cm
Thus, the fluid reaches up to
12.6
cm
12.6
cm
in the new cylinder.
