Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
Answer:
56
Step-by-step explanation:
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A. x=0, y=a*0+b=5, b=5
x=1, y=a*1+5=8, a=8-5, a=3
x=2, y=2*3+5=11
x=3, y=3*3+5=14
A is the answer
