1/2. Because 3 cancel 3 and 2 can go in 4 twice.
Answer:
See attachment for triangle
<em></em>
Step-by-step explanation:
Given
Shape: Equilateral triangle
![Perimeter = 10cm](https://tex.z-dn.net/?f=Perimeter%20%3D%2010cm)
Required
Draw the triangle
First, we determine the side lengths.
The perimeter of an equilateral triangle is:
![Perimeter = 3 * Length](https://tex.z-dn.net/?f=Perimeter%20%3D%203%20%2A%20Length)
So, we have:
![10= 3 * Length](https://tex.z-dn.net/?f=10%3D%203%20%2A%20Length)
Solve for Length
![Length = \frac{10}{3}](https://tex.z-dn.net/?f=Length%20%3D%20%5Cfrac%7B10%7D%7B3%7D)
![Length = 3.33](https://tex.z-dn.net/?f=Length%20%3D%203.33)
<em>See attachment for triangle</em>
Answer:
The possible lengths of the third side is all real numbers greater than 4 inches and less than 20 inches
Step-by-step explanation:
we know that
<u>The Triangle Inequality Theorem</u>. states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side
Let
x -----> the possible lengths of the third side
Applying the Inequality Theorem
1) 12+8 > x
20 > x
Rewrite
x < 20 in
2) 8+x > 12
x> 12-8
x > 4 in
therefore
4 in < x < 20 in
The possible lengths of the third side is all real numbers greater than 4 inches and less than 20 inches
Answer:
f(g(x)) = x² - 2x + 1
Step-by-step explanation:
To find f(g(x)), substitute x = g(x) into f(x) , that is
f(g(x))
= f(x - 1)
= (x - 1)² ← expand using FOIL
= x² - 2x + 1