The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample.
Slope, shmlope. What's the q?
Answer is 10(2k+5)
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Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
Answer:
(gof) (4) = 9
Hence, option A is true.
Step-by-step explanation:
f(x)=-x³
g(x)=|1/8x -1|
(gof) (4) = g{f(4)}
First wee need to determine f(4)
f(4)=-(4)³
= -64
so
(gof) (4) = g{f(4)} = g(-64)
= 
Thus,
(gof) (4) = 9
Hence, option A is true.
