Her situation can be modeled by the linear equation (in standard form):
x*$0.25 + y*$0.79 = $2.50
<h3>How to write the equation that represents her situation?</h3>
The variables that we will use here are:
x = number of apples that she can buy.
y = number of bananas that she can buy.
We know that she has $2.50 to spend, that each apple costs $0.25 and each banana costs $0.79, then the cost of the x apples and y bananas is:
x*$0.25 + y*$0.79
and that must be equal to the amount she has to spend, then we can write the linear equation:
x*$0.25 + y*$0.79 = $2.50
That is the linear equation in standard form that represents her situation.
Learn more about linear equations:
brainly.com/question/1884491
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Answer:
A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:
1) The other root is also a real number, but a different number
2) Its a repeated root, so the other root is the same number.
The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.
Following are 3 possibilities for the roots of a quadratic equation:
- 2 Real and Distinct roots
- 2 Real and Equal roots
- 2 Complex roots
The answer is -7
The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7
Hope that helps.
Answer:
-2=x
Step-by-step explanation:
-17=x-15
Add 15 on both sides
-2=x
Answer:
B. No, the remainder is -50.
General Formulas and Concepts:
<u>Algebra I</u>
- Roots are when the polynomial are equal to 0
<u>Algebra II</u>
Step-by-step explanation:
<u>Step 1: Define</u>
Function f(x) = x³ - 10x² + 27x - 12
Divisor/Root (x + 1)
<u>Step 2: Synthetic Division</u>
<em>See Attachment.</em>
To determine whether a given root is an actual root, the remainder must equal 0. Since we have a remainder of -50, the given root is not a factor of the polynomial.
<em>Please excuse the bad handwriting. Hope this helped!</em>
