<h2>
Dilations and Scale Factors</h2>
When we're solving with scale factors, we either divide or multiply.
If the shape becomes larger, we multiply to get the new length.
If the shape becomes smaller, we divide to get the new length.
<h2>Solving the Question</h2>
We're given:
- Original side length is 2.5 units
- Scale factor = 6
Because the shape becomes larger, we have to multiply the original side length by the scale factor, 6, to get the new side length.
2.5 x 6 = 15
Therefore, the missing side length is 15 units.
<h2>Answer</h2>
15 units
Answer:
Both expressions should be evaluated with two different values. If for each substituted value, the final values of the expressions are the same, then the two expressions must be equivalent.
Step-by-step explanation:
Both expressions are linear expressions. It takes 2 points to define a line. If the lines defined by each expression go through the same two points, then the expressions are equivalent.
If the expressions have the same value for two different variable values, they are equivalent. (choice D)
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<em>Additional comment</em>
One more point is needed than the degree of the polynomial expression. That is, quadratic (degree 2) expressions will be equivalent if they go through the same 2+1 = 3 points.
A) 0 represents the surface of the pool.
B) The height of the pool is 10 above the pool surface
C) It should be -3 since it is going down so it is going to be a negative number and it is also below the pool's surface.
Answer:

Step-by-step explanation:
Given



Required
Determine the coordinates of P
The coordinate of a point when divided into ratio is:

Where



This gives:




Answer:
3/1
Step-by-step explanation:
The average rate of change is the distance between y values divided by the distance between x values. We know this as rise/run or slope for linear equations. For non-linear equations, we calculate the average over an interval.
This function has y-values of -1 at x=0 and 5 at x=2.
We add -1+5=6 and divide this by 2-0=2.
6/2=3.
The y-values on average change 3 units for every 1 unit of the x-values.