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Anton [14]
3 years ago
11

3. Standard deviation is ________. a mean of squared differences the square root of the variance unit-free the covariance 4. Sta

ndard deviation is useful because it ________. provides a measure of deviation from the median has no units and can therefore apply to all data ignores outliers has the same units as the underlying data
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

3. Standard deviation is the square root of the variance.

4. Standard deviation is useful because it has the same units as the underlying data.

Step-by-step explanation:

3. In statistics, the dispersion in a given data with respect to its mean distribution can be determined or measured by standard deviation and variance. The standard deviation of a distribution can also be determined as the square root of variance.

4. Standard deviation is measured in the same units as that of the original data. Thus it has the same units as the underlying data.

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It’s confusing, would the answer be square root 7 over 4?
Colt1911 [192]

Answer:

\tan U = 1

Step-by-step explanation:

\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies UT^2 = UV^2 +VT^2\\\\\implies UV^2 = UT^2 -VT^2\\\\\implies UV^2 = \left(7\sqrt 2 \right)^2 - 7^2\\\\\implies UV^2 = 49(2)-49\\\\\implies UV^2 = 49\\\\\implies UV = \sqrt{49} \\\\ \implies UV = 7

\text{Now,}\\\\~~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan U = \dfrac{7}{7}\\\\\\\implies \tan U = 1

4 0
3 years ago
Explain why the following form linearly dependent sets of vectors. (solve this problem by inspection.)
Hunter-Best [27]

A set of vectors {v1,v2,...,vk} is linearly independent if the vector equation x1v1 + x2v2 + .......... + xkvk = 0 has only the trivial solution

x1 = x2 = .... = xk =0. Then the set  {v1,v2,...,vk} is linearly dependent otherwise.

So putting in the formula we get

x1u1 + x2u2 + x3u3 = 0

x1u1 + x2u2 = -x3u3

au1 + bu2 = u3               ∵ (-x1/x3 = a & -x2/x3 = b)

On putting in the values

a(3,-1) + b(4,5) = (-4,7)

(3a+4b,-a+5b) = (-4,7)

On comparing we get

3a + 4b = -4 -(1)

-a + 5b = 7  -(2)

on solving these equations we get

b = 17/19 and a= -48/19

which is non trivial.

Thus the following form linearly dependent sets of vectors.

Learn more about linear dependence of vectors here :

brainly.com/question/13776214

#SPJ4

7 0
2 years ago
PLEASE HELP ME I WILL GOVE BRAINLYEST
Tju [1.3M]
Question, do you need the angles? If it’s the angles use a protractor and measure.
8 0
2 years ago
Hi guys, how to calculate this in system?<br><br> {2a+3b=14<br> {5b+4a=20<br><br> Thanks,
Tom [10]

Step-by-step explanation:

there it is

and if u need more help tell me

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3 years ago
HELP I NEED HELP ASAP
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I think c) 9 but I’m not too sure
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