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3 years ago

A section at The top of the page that makes it easy for a recipient to respond to a letter is called an

Computers and Technology

2 answers:

Vesna [10]3 years ago

8 0

its a return address

Anika [276]3 years ago

8 0

Answer:

The correct answer to the following question will be a Return address.

Explanation:

Return Address:

The response of a person who sends the message can be given in the form of a return address.
It should include the details of the P.O box and the address (same as the delivery address).
Recipients should include, company's name.
This address located upper corner (left-hand side) in the envelope.

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Experimental probability describes how frequently an event actually occurred in an experiment. So if you tossed a coin 20 times and got heads 8 times, the experimental probability of getting heads would be 8/20, which is the same as 2/5, or 0.4, or 40%.

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2 years ago

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Write a function that accepts an argument for a persons name. The method should loop through the number of characters in the nam

MatroZZZ [7]

Answer:

#include <iostream>

#include<string.h>

using namespace std;

void printCharacter(string name){

for(int i=0;name[i]!='\0';i++){

cout<<name[i]<<endl;

}

int main()

{

string name;

cout<<"enter the name: ";

cin>>name;

printCharacter(name);

}

Explanation:

first include the two libraries iostream for input/output and string library for using the string.

then, create the main function and declare the variable type string.

cout instruction is used o display the message on the screen.

cin is used to store the value in the name variable.

after that, call the function. The program control move to the the function. In the function for loop is used to print the character one by one until end of the name.

4 0

3 years ago

Develop a C program that calculates the final score and the average score for a student from his/her (1)class participation, (2)

Ghella [55]

Answer:

#include <iomanip>

#include<iostream>

using namespace std;

int main(){

char name[100];

float classp, test, assgn, exam, prctscore,ave;

cout<<"Student Name: ";

cin.getline(name,100);

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

ave = (int)(classp + test + assgn + exam + prctscore)/5;

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

return 0;}

Explanation:

The required parameters such as cin, cout, etc. implies that the program is to be written in C++ (not C).

So, I answered the program using C++.

Line by line explanation is as follows;

This declares name as character of maximum size of 100 characters

char name[100];

This declares the grading items as float

float classp, test, assgn, exam, prctscore,ave;

This prompts the user for student name

cout<<"Student Name: ";

This gets the student name using getline

cin.getline(name,100);

This prompts the user for class participation. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Class Participation: "; cin>>classp;

while(classp <0 || classp > 100){ cout<<"Class Participation: "; cin>>classp; }

This prompts the user for test. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Test: "; cin>>test;

while(test <0 || test > 100){ cout<<"Test: "; cin>>test; }

This prompts the user for assignment. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Assignment: "; cin>>assgn;

while(assgn <0 || assgn > 100){ cout<<"Assignment: "; cin>>assgn; }

This prompts the user for examination. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Examination: "; cin>>exam;

while(exam <0 || exam > 100){ cout<<"Examination: "; cin>>exam; }

This prompts the user for practice score. The corresponding while loop ensures that the score s between 0 and 100 (inclusive)

cout<<"Practice Score: "; cin>>prctscore;

while(prctscore <0 || prctscore > 100){ cout<<"Practice Score: "; cin>>prctscore; }

This calculates the average of the grading items

ave = (int)(classp + test + assgn + exam + prctscore)/5;

This prints the calculated average

cout <<setprecision(1)<<fixed<<"The average score is "<<ave;

8 0

3 years ago