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omeli [17]
4 years ago
12

Find a - 2b + 3c diminished by a - 2b - 3c + d.

Mathematics
2 answers:
Rasek [7]4 years ago
7 0

a - 2b + 3c -(a - 2b - 3c + d)

=a - 2b + 3c -a + 2b + 3c - d

=6c -d

USPshnik [31]4 years ago
3 0

Answer:  The required value is 6c-d.

Step-by-step explanation:  We are given to find the following :

a-2b+3c diminished by a-2b-3c+d.

We know that

the expression p diminished by q is written as "p - q".

Therefore, the given expression implies

a-2b+3c~\textup{diminished by}~a-2b-3c+d\\\\=(a-2b+3c)-(a-2b-3c+d)\\\\=a-2b+3c-a+2b+3c-d\\\\=6c-d.

Thus, the required value is 6c-d.

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Sue walks 1 mile to a store. About how far is this in metric units? A. 2 millimeters B. Centimeters C. 2 meters D. Kilometers pl
Andrei [34K]

Answer:

C meter

Step-by-step explanation

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4 0
3 years ago
A garden measuring 15 meters by 20 meters is to have a pedestrian pathway installed
vfiekz [6]

The area of the garden is the amount of space on the garden.

  • The area of the total garden is (x + 15)(x + 20)
  • The width of the pathway is 1 meter

<h3>The expression of the area</h3>

The dimensions of the garden is given as:

15 meters by 20 meters

Let the width of the pedestrian pathway be x.

So, the area of the total garden is:

Area=(x + 15)(x + 20)

<h3>The width of the pathway</h3>

In (a), we have:

Area=(x + 15)(x + 20)

The total area is given as: 336.

So, we have:

(x + 15)(x + 20) = 336

Expand

x^2 + 35x + 300 = 336

Collect like terms

x^2 + 35x + 300 - 336 = 0

Evaluate

x^2 + 35x - 36 = 0

Expand

x^2 + 36x -x - 36 = 0

Factorize

x(x + 36) -1(x +36) = 0

Factor out x + 36

(x + 36)(x -1) = 0

Solve for x

x = -36 or x =1

The width cannot be negative.

Hence, the width of the pathway is 1 meter

Read more about areas at:

brainly.com/question/24487155

8 0
3 years ago
What’s 40 41 42 43 44 45 46 47 48 49 50 IQR pls fast!!!!!
aliina [53]

Answer:

IQR = 6

Step-by-step explanation:

Given:

The given set of data is:

40 41 42 43 44 45 46 47 48 49 50

Number of terms, n=11

Therefore, the median is given as (\frac{n+1}{2})^{th} term which is the sixth term. Median = 45

(40 41 42 43 44) <u>45</u> (46 47 48 49 50 )

Now, we find the median of the lower half (Q_1) and upper half (Q_3)of the data that are before and after the median.

The lower half of the data has the values 40 41 <u>42</u> 43 44.

Number of terms are 5. So, median is the third term which is, Q_1=42

The upper half of the data has the values 46 47 <u>48</u> 49 50.

Number of terms are 5. So, median is the third term which is, Q_3=48

Now, IQR is given as the difference of upper half median and lower half median.

IQR=Q_3-Q_1\\IQR=48-42=6

4 0
4 years ago
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3rd out of 10 questions<br> For a cooking class, Tom earns 4 points for each meal that he cooks.
Pani-rosa [81]
The ratio would be 1 meal : 4 points.
6 0
3 years ago
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Solve <br> r squared+7r+6=0
Whitepunk [10]

Answer:

r=-6

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Step-by-step explanation:

r^2+7r+6\\(r+6)(r+1)=0\\\\r+6=0\\r=-6\\\\r+1=0\\r=-1

6 0
3 years ago
Read 2 more answers
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