Answer: (1st box) = 6 (2nd box) = 2 (3rd box) = 2/3
Step-by-step explanation:
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
a0) 2
x<0
a1) x
0≤x<3
a2) 3
x≥3
Step-by-step explanation:
As shown in the given graph
function of y is a straight line at y=2 line till x=0
hence a0:
y= 2 for x<0
Then function becomes linear line from x=0 till x=3
hence a1:
y= x for 0≤x<3
Now after that graph of function y again shift to straight line from x=3 onward with y-axis value of 3
hence a2:
y= 3 for x≥3 !
