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Gennadij [26K]
3 years ago
5

Write 9/8 in atleast 3 different ways as a sum of fractions

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

1/8+1 OR 1/8 +8/8

2/8+7/8 OR 1/4+7/8

3/8+6/8 OR 3/8+3/4

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Is(5, 6)a solution to the inequality<br> y &lt; 2x + 4 ?
Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0
3 years ago
I need help with this please pls pls
Masja [62]

Answer:in what ?

Step-by-step explanation:

7 0
3 years ago
What is the derivative of 3x+5x
Vaselesa [24]

Answer:

\displaystyle \frac{d}{dx}[3x + 5x] = 8

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle y = 3x + 5x

<u>Step 2: Differentiate</u>

  1. Simplify:                                                                                                         \displaystyle y = 8x
  2. Derivative Property [Multiplied Constant]:                                                   \displaystyle y' = 8\frac{d}{dx}[x]
  3. Basic Power Rule:                                                                                         \displaystyle y' = 8

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

5 0
3 years ago
Simplify by using the law of indices:<br>y^a(b+c)×y^b(c-a)×y^c(a-b)​
tia_tia [17]

Answer:

y^{2ac}

Step-by-step explanation:

Using the law if indices

a^{m} × a^{n} = a^{(m+n)}

Thus to simplify the expression add the 3 exponents

a(b + c) + b(c - a) + c(a - b) ← distribute parenthesis

= ab + ac + bc - ab + ac - bc ← collect like terms

= 2ac

Then the expression simplifies to

y^{2ac}

4 0
3 years ago
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