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3 years ago

Write 9/8 in atleast 3 different ways as a sum of fractions

Mathematics

1 answer:

Vlad1618 [11]3 years ago

7 0

Answer:

1/8+1 OR 1/8 +8/8

2/8+7/8 OR 1/4+7/8

3/8+6/8 OR 3/8+3/4

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Is(5, 6)a solution to the inequality y < 2x + 4 ?

Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0

3 years ago

I need help with this please pls pls

Masja [62]

Answer:in what ?

Step-by-step explanation:

7 0

3 years ago

What is the derivative of 3x+5x

Vaselesa [24]

Answer:

$\displaystyle \frac{d}{dx}[3x + 5x] = 8$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = 3x + 5x$

Step 2: Differentiate

Simplify: $\displaystyle y = 8x$
Derivative Property [Multiplied Constant]: $\displaystyle y' = 8\frac{d}{dx}[x]$
Basic Power Rule: $\displaystyle y' = 8$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago

How to solve this? \int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$