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lana66690 [7]
3 years ago
12

Name the angles that are complements to SWT

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer:

The correct answer is C) USP and TSV.

I just finished the test and it was correct.

Hope this helps!!!!!!

<h2>:)</h2>

zlopas [31]3 years ago
7 0
Two angles are said to be complementary, if the sum of the two angles is 90 degrees.

Given that the measure of angle SWT is 50 degrees, thus, the measure of the complementary angles will be 90 - 50 = 40 degrees.

From the diagram, the measure of angle USP is 40 degrees, hence it is a complement of angle SWT.

Recall that the angle on a straight line is equal to 180 degrees, thus the sum of the measures of angles USP, WST and TSV is 180 degrees.
i.e. mUSP + mWST + mTSV = 180 degrees
40 + 100 + mTSV = 180
mTSV = 180 - 140 = 40 degrees.
Hence angle TSV is complementary to angle SWT.

Therefore, the complementary angles to angle SWT are angle USP and angle TSV.
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Solution -9-8(1+4h)= -17
geniusboy [140]
Step 1. <span>Add </span>9<span> to both sides

</span>-8(1+4h)=-17+9

Step 2. Simplify -17+9 to -8

-8(1+4h)=-8

Step 3. Divide both sides by -8

1+4h=1

Step 4. Cancel 1 on both sides

4h=0
 Step 5. Divide both sides by 4

h=0

Done! :) Hope this helps! :)

To check -9-8(1+4h)=-17 follow these steps below:

Step 1. Let h = 0

-9-8*(1+4*0)=-17

Step 2. Simplify 4 * 0 to 0

-9-8*(1+0)=-17

Step 3. Simplify 1 + 0 to 1

-9-8*1=-17
<span>
Step 4. </span><span>Simplify  8 * 1 to 8
</span>
-9-8=-17
<span>
Step 5. </span><span>Simplify -9 -8 to -17
</span><span>
</span>-17=-17
<span>
Done! :)
 </span>
5 0
3 years ago
Read 2 more answers
6<br> b<br> 2<br> a<br> 6<br> same result
Luba_88 [7]

Answer:

go to this link

Step-by-step explanation:

Videos

2:41

Manipulating expressions using structure (example 2) (video)

8 0
2 years ago
Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
Makovka662 [10]

Answer:

The answer is C.

Step-by-step explanation:

Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.

In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

h(t)=-16t2+38t+30

When the object hits the ground, h=0.

h=-16t2+38t+30=0

Simplifying 8t2-19t-15=0

(8t+5)(t-3)=0

t=-5/8 or 3

As time cannot be -ve, t=3s. The answer is C.

6 0
2 years ago
Read 2 more answers
Choose the correct simplification of the expression (−2x + 8y)(9x − 3y).
Romashka-Z-Leto [24]
For these kinds of expressions use FOIL (first, outside, inside, last).

-2x • 9x = -18x^2
-2x • -3y = 6xy
8y • 9x = 72 xy
8y • -3y = -24y^2

Now combine them all:

-18x^2 + 78xy - 24y^2
6 0
3 years ago
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What is the slope of the line through (3,2) and (-3,4)?
NISA [10]

Answer:

slope = - \frac{1}{3}

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (3, 2 ) and (x₂, y₂ ) = (- 3, 4 )

m = \frac{4-2}{-3-3} = \frac{2}{-6} = - \frac{1}{3}

3 0
1 year ago
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