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Kay [80]
3 years ago
8

Solve for x. - 1 = 3x - 7 Simplify your answer as much as possible. X =

Mathematics
2 answers:
Maurinko [17]3 years ago
5 0

Answer:

x=2

Step-by-step explanation:

-1=3x-7

Add both sides by 7 to isolate 3x

-1+7=3x-7+7

6=3x

Divide both sides by 3 to isolate x

6/3=3x/3

2=x

I hope this helps!

SVEN [57.7K]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

-1=3x-7

-1+7=3x

6=3x

x=<u>6</u>

<u> </u><u> </u><u> </u><u> </u>3

x=2

hope it helps.

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If p→qp→q, and q→rq→r, then thats all it says
Angelina_Jolie [31]
Answer: then q→r

Explanation:

If p → q

and q →r , then  you can use the law of transitivity to conclude

q→r.

That is a basic law of sillogisms.

An example will help you to understand the transivity law:

Make p, stand for 3 > 3/4, q stand for 3/4 > 15 / 20, the you can conclude that 3 > 15 / 20.

3 > 3/4

3 /4 > 15 / 20

Then, 3 > 15 /20.

This is, from the fact that you know that 3 is gretar than 3/4 and that 3/4 is greater than 15/20, you can conclude that 3 > 15 / 20. That is transitivity and is a law of logic, which you can use to get conclusions.
8 0
3 years ago
A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
For the equation 3x - 5y = -3, what is the value ofy when x is 1?<br> 6/5<br> -6/5<br> 5/6
Law Incorporation [45]

Answer:

y = 6/5

Step-by-step explanation:

3x - 5y = -3

Let x =1

3(1) - 5y = -3

3-5y = -3

Subtract 3 from each side

3-3-5y = -3-3

-5y = -6

Divide each side by -5

-5y/-5 = -6/-5

y = 6/5

8 0
3 years ago
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Ierofanga [76]

Answer:

Hey there!

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If it is a multiple of 10, it has to be a multiple of 5. Thus, the only thing we need to do now, is find the LCM of 10 and 7, which is 70.

Thus, your answer is 70.

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8 0
3 years ago
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What are the slope and the y-intercept of the graph of the linear function shown on the grid?
poizon [28]
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3 years ago
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