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2 years ago

14

Jacob had a cube. When Jacob made a cross section parallel to the base, what shape did the cross section form? trapezoid square

parallel triangle

1 answer:

vivado [14]2 years ago

4 0

Answer: Square

Step-by-step explanation:

A cross section cut parallel to a base will be the same shape as the base itself, and the base of a cube is a square. :)

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Points are: A= (-2,7)B= (3,5)C= (1,0) To show that the triangle is a right triangle, show that the sum of the squares of the len

Gala2k [10]

The sum of the squares of the lengths is 58

The square of length of the hypotenuse is 58

From the question, we have

AB² = (-2-3)² +(7-5)²= 25+4 =29

BC² = (3-1)²+(5-0)²=4+25=29

AC² = (-2-1)²+(7-0)² = 9+49 = 58

Here we can see that,

AB²+BC² = AC²

The sum of the squares of the lengths of two sides (the legs) equals the square length of the third side (hypotenuse).

the sum of the squares of the lengths = AB²+BC² =29+29 = 58

the square of length of the hypotenuse= 58

Pythagoras Theorem:

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.

To learn more about pythagoras theorem visit: brainly.com/question/343682

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1 year ago

Grayson is flying a kite, holding his hands a distance of 2.75 feet above the ground and letting all the kite’s string play out.

sergiy2304 [10]

The position of the kite with the point directly beneath the kite at the same

level with the hand and the hand for a right triangle.

The height of the kite above the is approximately <u>66.314 feet</u>.

Reasons:

The height of his hands above the ground, h = 2.75 feet

Angle of elevation of the string (above the horizontal), θ = 26°

Length of the string, <em>l</em> = 145 feet

Required:

The height of the kite above the ground.

Solution:

The height of the kite above the ground is given by trigonometric ratios as follows;

$\displaystyle Height \ of \ kite, \, k_h = \mathbf{h + l \times sin(\theta)}$

Therefore;

$\displaystyle Height \ of \ kite, \, k_h = 2.75 + 145 \times sin(26^{\circ}) \approx \mathbf{66.314}$

The height of the kite above the, $k_h$ ≈ <u>66.314 feet</u>

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3 years ago

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liubo4ka [24]

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