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MA_775_DIABLO [31]
3 years ago
7

How can you proportional relationship be graphed ?

Mathematics
1 answer:
Strike441 [17]3 years ago
5 0
To graph proportional relationships always start at (0,0) which is the y-intercept then graph the points, for example y=x+2 is a proportional relationship, go up 2 over 2. I hoped that helped.. math isn't my best subject but I learned about this from last year.
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Find the distance between the two points in simplest radical form.<br> (-9,5) and (0,0)
7nadin3 [17]

Answer:

\sqrt{106} units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 9, 5)

d = \sqrt{(-9-0)^2+(5-0)^2}

   = \sqrt{(-9)^2+5^2}

   = \sqrt{81+25}

    = \sqrt{106}

 

3 0
3 years ago
Which type of line of symmetry does the figure have? <br>​
9966 [12]

Answer:vertical

Step-by-step explanation:

4 0
3 years ago
Which point is the solution to the system of equations graphed?
Mazyrski [523]

Answer: B. (3,3)


Step-by-step explanation:

B is correct because the lines intersect at the one point, meaning there is only one solution, B.

Good luck and I hope this helps!

Tip: Follow and message me for daily help on all subjects! :)

7 0
3 years ago
Log_c(A)=2<br> log_c(B)=5, <br> solve log_c(A^5B^3)
vlabodo [156]

We know that \log_a(bc)=\log_a(b)+\log_a(c).

Using this rule,

\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3).

We also know that \log_c(a^b)=b\log_c(a).

Using this rule,

\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)

Now we know that \log_c(A)=2,\log_c(B)=5 so,

5\cdot2+3\cdot5=10+15=\boxed{25}.

Hope this helps :)

3 0
3 years ago
The volume of a cube is 343mm3.<br> What is the length of its side?
stiv31 [10]

Answer:

Step-by-step explanation:

s is the length of each side of the cube

volume = s³

343 = s³

s = ∛343 = 7 mm

5 0
3 years ago
Read 2 more answers
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