Answer:
y = 56/3
Step-by-step explanation:
We need to write equations to solve
Let the two numbers be x and y
The sum is 56
x+y = 56
The first number is 2 times greater than the second number.
x = 2*y
Substitute this into the first equation
x+y = 56
2y+y=56
3y = 56
y = 56/3
Answer:
b
Step-by-step explanation:
1) split the range in three identical invervals of size [6 - 0] / 3 = 2
2) form three rectangles
2a) First rectangle: base 2, height f(2) = 2^2 + 1 = 5
area 1 = base * height = 2 * 5 = 10
2b) second rectangle: base 2, height f(2+2) = 4^2 + 1 = 17
area 2 = 2 * 17 = 34
2c) third rectangle: base 2 height f(4+2) = 6^2 + 1 = 37
area 3 = 2*37 = 74
3) total area = area 1 + area 2 + area 3 = 10 + 34 + 74 = 118
Answer:
p= 3
q= 7
Hope this helps :)
Answer:
45= v
Step-by-step explanation:
9 = v/5
Multiply each side by 5
9*5 = v/5*5
45 =v
