Question

The net of a pyramid is shown below. The surface area of the solid is ____ square inches.

Answer 1

Answer:

$\text{Total surface area of net pyramid}=80\text{ in}^2$

Step-by-step explanation:

We have been given a net pyramid and we are asked to find the total surface area of our given pyramid.

The total surface area of our given pyramid will be equal to the area of 4 triangles plus area of middle square.

$\text{Area of triangle}=\frac{1}{2}\times\text{Base*Height}$

$\text{Area of triangle}=\frac{1}{2}\times\text{8 in}*\text{4 in}$

$\text{Area of triangle}=\frac{1}{2}\times 32\text{ in}^2$

$\text{Area of triangle}=16\text{ in}^2$

$\text{Area of 4 triangles}=4\times 16\text{ in}^2$

$\text{Area of 4 triangles}=64\text{ in}^2$

$\text{Area of middle square}=\text{4 in}*\text{4 in}$

$\text{Area of middle square}=16\text{ in}^2$

Now let us add these areas to find the total surface area of our given net pyramid.

$\text{Total surface area of net pyramid}=16\text{ in}^2+64\text{ in}^2$

$\text{Total surface area of net pyramid}=80\text{ in}^2$

Therefore, the total surface area of our given net pyramid is 80 square units.

Answer 2

Area of a triangle= bh/2b=4in h=8in8x4/2=16in
there are 4 triangles
4x16=64
area of a rectangle=bh
4x4=16
64+16=80in^2