Ask question

Ask question

All categories

3 years ago

13

Claire has 15 green beads 8 blue beads and 4 yellow beads. If she puts them onto 3 strings equally how many beads are on each st

ring?

2 answers:

zhenek [66]3 years ago

5 0

Nine, cause 8+4+3= 27! And I think, since there's 3 bead types you divide it by three. Which is nine!!

Katyanochek1 [597]3 years ago

4 0

There are 9 beads on each string

You might be interested in

Help me and EXPLAIN plz

dalvyx [7]

Volume=length X breadth X height

hence, volume= 9.6 X 5 X 7 cubic millimeters

which is equal to 336 cubic mm

5 0

3 years ago

Length and breadth of a rectangular field is 5 : 3. If the breadth of rectangle is 60m, find the length of the rectangle.

djverab [1.8K]

Answer:

5m

Step-by-step explanation:

Given data

Ratio of length to breadth is 5 : 3

hence in fraction form it is 5/3

the breadth of rectangle is 60m

let the length be x

So

5/3= x/3

cross multiply we have

5*3= 3x

15= 3x

divide both sides by 3

x= 15/3

x= 5m

Hence the length is 5m

3 0

3 years ago

Please<br> Help fast I have 25 mins left

castortr0y [4]

Answer:

Step-by-step explanation:

sales earning commission=130,000-21000=109,000

sales commission=5800-900=4900

rate of commission=4900/109,000 ×100=490/109 %

≈4.495

≈4.50%

4 0

3 years ago

A plane and a line can intersect in a point true or false

tester [92]

Answer:

True

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A geologist has collected 5 specimens of basaltic rock and 7 specimens of granite. The geologist instructs a laboratory assistan

MaRussiya [10]

The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:

$E(X) = 5.25, Var(X) = 0.5966$
P(X < 6) = 0.9545
P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The mean and the variance are:

$\mu = \frac{nk}{N}$

$\sigma^2 = \frac{nk(N-k)(N-n)}{N^2(N-1)}$

We have that:

5 + 7 = 12 rocks, which means that $N = 12$

9 are chosen, which means that $n = 9$

7 are granite, which means that $k = 7$

Question a:

$E(X) = \mu = \frac{9\times7}{12} = 5.25$

$Var(X) = \sigma^2 = \frac{9\times7(12-7)(12-9)}{12^2(12-1)} = 0.5966$

Thus:

$E(X) = 5.25, Var(X) = 0.5966$

Question b:

Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,12,9,7) = \frac{C_{7,4}*C_{5,5}}{C_{12,9}} = 0.1591$

$P(X = 5) = h(5,12,9,7) = \frac{C_{7,5}*C_{5,4}}{C_{12,9}} = 0.4773$

$P(X = 6) = h(6,12,9,7) = \frac{C_{7,6}*C_{5,3}}{C_{12,9}} = 0.3181$

Thus

$P(X < 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1591 + 0.4773 + 0.3181 = 0.9545$

So P(X < 6) = 0.9545.

Question c:

5 of basaltic and 4 of granite: 0.1591 probability.

7 of granite is P(X = 7), in which

$P(X = 7) = h(7,12,9,7) = \frac{C_{7,7}*C_{5,2}}{C_{12,9}} = 0.0455$

0.1591 + 0.0455 = 0.2046, thus:

P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.

A similar question is found at brainly.com/question/24008577

5 0

3 years ago