For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
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(√6,0) (√5,-1) (-√6,0) (-√5,-1)
Answer:
c.
Step-by-step explanation:
If its isoceles, then LM is equal to LN. This means 3x-2 = 2x+1. 3x minus 2x is x. 2 plus 1 is 3. So x = 3. So it needs to be c or d. since LM and LN are the same answers, go to MN and find the answer. If you siubstitute 3 for x in 5x-2, then you get 13.
Answer: 26.1
<u>Step-by-step explanation:</u>
Answer:
ac
Step-by-step explanation:
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