The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer
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Step-by-step explanation:
$104 because 30% of $80 is $24 and $80+$24 is $124 so...... that's what I got
Answer:
4(2x-3)(2x + 3)
Step-by-step explanation:
Here, we want to simplify the given expression
we can have;
16x^2-36
= 4(4x^2 -9)
we can use the difference of two squares
where;
a^2 - b^2 = (a-b)(a + b)
= 4(2x-3)(2x+ 3)
Answer:
Step-by-step explanation:
The factor pairs of 6 are 1×6 and 2×3
So the parallelogram (height by length) could be:
1 by 6
2 by 3
3 by 2
6 by 1