Answer:
The lateral area is 
Step-by-step explanation:
we know that
The lateral area of a right prism is equal to
where
P is the perimeter of the base of the prism
H is the height of the prism
in this problem we have
substitute
Answer:
First, we need to determine the slope of the line going through the two points. The slope can be found by using the formula:
m
=
y
2
−
y
1
x
2
−
x
1
Where
m
is the slope and (
x
1
,
y
1
) and (
x
2
,
y
2
) are the two points on the line.
Substituting the values from the points in the problem gives:
m
=
5
−
7
3
−
0
=
−
2
3
Now, we can use the point-slope formula to find an equation going through the two points. The point-slope formula states:
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Where
m
is the slope and
(
x
1
y
1
)
is a point the line passes through.
Substituting the slope we calculated and the values from the first point gives:
(
y
−
7
)
=
−
2
3
(
x
−
0
)
We can also substitute the slope we calculated and the values from the second point giving:
(
y
−
5
)
=
−
2
3
(
x
−
3
)
We can also solve the first equation for
y
to transform the equation to slope-intercept form. The slope-intercept form of a linear equation is:
y
=
m
x
+
b
Where
m
is the slope and
b
is the y-intercept value.
y
−
7
=
−
2
3
x
y
−
7
+
7
=
−
2
3
x
+
7
y
−
0
=
−
2
3
x
+
7
y
=
−
2
3
x
+
7
Answer:
that is 70° I hope you get a A+
I think there's an easy way and a hard way to do this, and I think that the way
I'm about to describe is the easier way.
Probability = (number of successful outcomes)/(total number of possible outcomes)
<em>How many total pairs can be drawn from 8 total pens ?</em>
-- The first one drawn can be any one of 8 pens. For each of these . . .
-- The second one drawn can be any one of the remaining 7 .
-- Total number of ways of drawing a pair = (8 x 7) = 56 ways.
-- But there aren't 56 different different pairs. Whether you draw A and then B,
or B and then A, you wind up with the same pair. There are 2 different ways to
draw each pair, so the 56 ways of drawing a pair only produces <u>28</u> different pairs.
<u>How many pairs are two of the same color ?</u>
<em>Possible number of blue pairs:</em>
The reasoning is exactly the same as calculating the TOTAL number of
pairs, as explained above.
With 5 blue pens, you can make <u>10</u> different pairs.
AB, AC, AD, AE, BC, BD, BE, CD, CE, and DE.
<em>Possible number of red pairs:</em>
The reasoning is exactly the same as calculating the TOTAL number of
pairs, as explained above.
With 3 red pens, you can make <u>3</u> different pairs.
AB, AC, and BC.
Total number of possible same-color pairs = 10 + 3 = 13
successes / total possible outcomes = 13/28 = <u>46.4</u>% (rounded)
