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Xelga [282]
4 years ago
12

Jackson said, "I am thinking of two

Mathematics
1 answer:
weeeeeb [17]4 years ago
3 0
1/2+1/2 could be a possibility.
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Pls help me before I have another mental breakdown
Lyrx [107]

Answer:

a) fog(x) = (x-2)⁴ +4

b) (g o f) (x) = x⁴ + 2

c) hog(x) = \sqrt{x-2}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the function

f(x) = x⁴+4 , g(x) = x-2 , h(x) = √x

f o g (x) = f(g(x))

           = f(x-2)

         = (x-2)⁴ +4  (∵ f(x) = x⁴ +4))

fog(x) = (x-2)⁴ +4

<u><em>Step(ii):-</em></u>

(g o f) (x)  = g(f(x))

              = g(x⁴ +4)

             =  x⁴ +4 -2   ( ∵ g(x) = x-2)

            = x⁴ + 2

(g o f) (x) = x⁴ + 2

<u><em>Step(iii)</em></u>:-

hog(x) = h(g(x))

         = h(x-2)

         =  \sqrt{x-2}    

 hog(x) = \sqrt{x-2}

3 0
3 years ago
Find (-3/7) divided (-1 1/14)
Andrews [41]

Answer:

2/5

Step-by-step explanation:

first, we convert the mixed fractions to improper fractions,

-1\frac{1}{14}=\frac{15}{14}

so then we find what -\frac{3}{7}\div-\frac{15}{14}

-\frac{3}{7}\div-\frac{15}{14} = -\frac{3}{7} * -\frac{14}{15}

and that equals \frac{3*14}{7*15} , which equals \frac{42}{105}. We can simplify that to 2/5

3 0
3 years ago
Pls help<br> Enter the equation for the graph.
prisoha [69]

Answer:

y=[1]cos([\frac{2\pi }{3}]x)

Step-by-step explanation:

Looking at the graph, we can see the domain to be from (0 , 2π).

Now we have to find one period that corresponds to cos(x).

The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.

b = 2pi/3

a is the same range as cos(x). Range: (0,0)

y = [a] * cos ([b]*x)

y = [1] * cos([2pi/3]x)

4 0
2 years ago
A spinner with 10 equally sized slices has 10 yellow slices. The dial is spun and stops on a slice at random. What is the probab
djverab [1.8K]

Answer:

1/10

Step-by-step explanation:

there are 10 slices, so if the probability of it landing on one of them is 1/10

5 0
3 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1436 referee​ calls, with the re
Artemon [7]

There is no sufficient evidence to suggest that men and women have equal success in challenging calls. This was illustrated in the hypothesis.

<h3>How to compute the value?</h3>

It should be noted that based on the information given, P1 will be:

= 424/1436

= 0.295

P2 will be:

= 222/754

= 0.294

The value of the test statistic will be:

= (424 + 222)/(1436 + 754)

= 646/2190

= 0.2949

In this case, the value of the test statistic falls on the rejection region, therefore, there is no sufficient evidence to suggest that men and women have equal success in challenging calls.

Learn more about hypothesis on:

brainly.com/question/11555274

#SPJ1

4 0
2 years ago
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