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GaryK [48]
3 years ago
8

which of the following Expressions could be interpreted as "a number times negative seven added to five equals two"?​

Mathematics
2 answers:
Brrunno [24]3 years ago
5 0

Answer:

It depends on how you interpret the statement.

( x * -7 ) + ( 5 - 2 )

x * ( -7 + 5 ) - 2

Step-by-step explanation:

"a number times negative seven added to five equals two"

Let's set x as our number.

So the statement would translate to:

x * -7 + 5 - 2

To simplify, we might try to organize things by adding some parentheses. But that's when things start to get a little.....dicey.

Depending on how you interpret the original statement, both (x*-7)+5-2 and x*(-7+5)-2 can satisfy the statement.

Herein lies our problem. Which of the two expressions is correct?

Well.....both of them, actually. It just depends on how you're interpreting the statement and what options you have available.

If you can only pick one, but all of the expressions are possible options, then you're kind of stuck.

ryzh [129]3 years ago
3 0
X(-7)+5=2 it can be this
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Answer:

-0.5 ,0.75

Step-by-step explanation:

4 \times t^{2}=t+6


\therefore 4 \times t^{2}-t-6 = 0

therefore t=\frac{1\mp\sqrt{1+24}}{8}

[                 =\frac{1\mp\sqrt{25}}{8}

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3 years ago
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GarryVolchara [31]

Answer:

No

Step-by-step explanation:

the first one would be 65 and 23/1000, while the other one is 65 and 23/100

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You flip a coin 5 times. in how many ways could u obtain at least one tail
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- Flip 1 can either be heads or tails
- Flip 2 can either be heads or tails

So our possible outcomes are HH, HT, TH, and TT. There are two possible second flips <em />for <em>each</em> of the possible first flips, or 2 x 2 = 4 total combinations of flips. Notice that <em>only one </em>of those combinations has zero tails - the combination with all heads.

If we were to flip a coin 5 times, we'd have two possible fifth flips for each of the two possible fourth flips for each of the two possible third flips for... it gets pretty hairy to describe in words, but I've attached a diagram so you can see how quickly it grows out of control. There are 2 x 2 x 2 x 2 x 2 or 2^5=32 possible combinations of heads and tails! But, in fact, we don't even need to sort through these 32 combinations to answer our question. <em>Every</em> combination will contain at least one tail, except one: the combination which contains all heads (HHHHH). Which means the rest of the 31 must contain at least one tail.

This fact will stay the same regardless of the number of coin flips you make: <em>the number of ways that contain at least one tail will always be the total number of combinations minus one (the case where all of the flips are heads).</em>

5 0
4 years ago
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