Here, we are required to determine how many hours your friend will drive in order to catch you.
(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>
<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>
If you leave at 1 pm; At 2:30pm;
- That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
- d = 112.5miles.
Therefore, your position; S after 2:30pm is given by;
S(a) = 75t + 112.5 miles from Ellensburg.
For your friend; travelling at 90miles/hr;
- His position is given as; S(b) = 90 × t
(a) For your friend to catch you, you both must be in the same position;
75t + 112.5 = 90t
90t -75t = 112.5
t = 112.5/15
t = 7.5hours
(b) To determine how far you both are from Ellensburg; we can either evaluate:
S(b) = 90t or S(a) = 75t + 112.5
Therefore, By evaluating S(b) = 90t.
S(b) = 90 × 7.5
S(b) = 675miles from Ellensburg.
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Answer:
y = 8 or y = -14
Step-by-step explanation:
Solve for y over the real numbers:
abs(y + 3) - 4 = 7
Add 4 to both sides:
abs(y + 3) = 11
Split the equation into two possible cases:
y + 3 = 11 or y + 3 = -11
Subtract 3 from both sides:
y = 8 or y + 3 = -11
Subtract 3 from both sides:
Answer: y = 8 or y = -14
The producy means multiplication so : 6256 ×486=
=3,040,416
(-2n -2)/3= 12
⇒ -2n -2= 12*3
⇒ -2n -2= 36
⇒ -2n= 36+ 2
⇒ -2n= 38
⇒ n= 38/(-2)
⇒ n= -19
Final answer: n=-19~