1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sammy [17]
3 years ago
12

Drag each tile to the correct box.

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

1. 50 cm

2. 550 mm

3. 5000 mm

4. 5000 cm

5. 5000 m

Step-by-step explanation:

We can convert all the measures in same unit to arrange them one by one.

5000 cm:

As there are 10 millimeters in 1 cm,

5000 cm = 5000*10mm

=> 50000 mm

5000 meters:

As there are 100 cms in one meter

5000 m = 5000*100 cm

=> 500000 cm

Now to convert in millimeter

500000*10= 5000000 mm

50 cm:

50*10 = 500 mm

Then there is 550 mm and 5000 mm

So, the order from least to greatest is:

1. 500 mm which is equivalent of 50 cm

2. 550 mm

3. 5000 mm

4. 50000 mm which was equivalent of 5000 cm

5. 5000000 mm which was equivalent of 5000 m ..

You might be interested in
How many moles are in 25g of CO2?<br><br> With calculation show please
GuDViN [60]
Here’s the answer! Let me know if you have any questions
5 0
3 years ago
Read 2 more answers
The conditional relative frequency table below was generated by column using frequency table data comparing the number of calori
inessss [21]

Answer:

B. There is an association because the value 0.15 is not similar to the value 0.55

Step-by-step explanation:

Based on the above picture, for the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.

The conditions that satisfy whether there exists an association between conditional relative frequencies are:

1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.

2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.

For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

We can conclude that there is an association because the value 0.15 is not similar to the value 0.55

3 0
3 years ago
Read 2 more answers
Find the slope of the graph of the equation <br> 3x + 15y = 25<br> (Please show your work)
pantera1 [17]
Answer:

y= - 1/5x + 5/3
3 0
3 years ago
Read 2 more answers
There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

-

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
Express each fraction as a percent. Round your answer to the nearest whole number. 76/125
BartSMP [9]

Answer:

  61%

Step-by-step explanation:

Multiply the fraction by 100%.

  76/125 × 100% = (7600/125)% = 60.8% ≈ 61%

3 0
3 years ago
Other questions:
  • We can use a right triangle to model half of the bridge. So we can use the _____ Theorem to solve this problem.
    6·1 answer
  • Which statement allows for us to conclude that line m and line n are parallel?
    13·1 answer
  • Can someone please answer this it would mean the world to me cause im failing right now
    5·1 answer
  • Ivan has just opened a small coffee shop. He paid a copy store 0.10 per copy to make 1428 copies of the flyer to announce the op
    12·1 answer
  • find two consecutive integers such that their sum equal to the difference of three times the larger and two times the smaller
    12·1 answer
  • Vickie bought 54 tickets for a ride at an amusement park.each ride cost 3 tickets and Vickie has been on x rides so far.which ex
    14·1 answer
  • If 1/2 of a given number is 12, what is one third of a given number
    10·1 answer
  • The graph shows the earnings of you and your friend for babysitting
    9·1 answer
  • One lap around the track on the playground is 1/9 mile. The 5th grade teachers walked 10 laps. How many miles did they walk
    6·1 answer
  • Expand . ( 3x –2 ) 2 please help me with this.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!