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statuscvo [17]
3 years ago
8

A waterfall has a height of 1400 feet. A pebble is thrown upward from the top of the falls with an initial velocity of 12 feet p

er second. The​ height, h, of the pebble after t seconds is given by the equation h equals negative 16 t squared plus 12 t plus 1400
h=−16t2+12t+1400. How long after the pebble is thrown will it hit the​ ground?
Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0
I think the answer is 10
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