Hello!
I believe the answer is ultimately Fossils, seeing how fossils from one edge of a continent could be found on the edge of another continent in which is theorized they were once bonded.
I hope this helps and I'd like a Brainliest if anyone else has answered. It's alright if not. Have a nice day. :)
Answer:
Let’s assume that the projectile has the same initial velocity in both cases. It is necessary to find that velocity.
u = u[x]i +u[y]j = [u cos 15]i + [u sin 15]j
The p.v. ; s = s[x]i +s[y]j , get the time of flight by letting s[y]=0
s[y] = [u(y)].t -[1/2]gt^2 =0 , so t = 2u[y]/g
t = [ 2 u sin 15]/g eq 1
s[x] = [ u cos 15] .t eq 2 , substitute in eq q into eq2
range =r = [ u cos 15 ][ 2u sin 15 ]/g =[u^2/g][ 2 sin 15 . cos 15],
r =[ u^2 sin 30]/g =1.5 km
( from this we see that ,in general, r = [u^2 .sin (2a)]/g
u^2 = [ 3g] , eq 1
Now do the 2 nd part
r[2] = [u^2 sin (2a)]/g , eq 2 Let a =45 and substitute eq 1 into eq 2
r[2] = [3g sin 90]/g
r[2] =3 km.
Explanation:
Answer:newton’s third law is that all the forces in the universe occur an equal and opposite pairs.
Explanation: this basically means that all the forces in the world like mass and weight have multiple things in common but yet are totally different. mass can be compared to weight but it is different because it has its own factors that make
it different. therefore, newton’s third law basically means that forces like mass and weight are equal and similar in a way but have factors that make it different as well.
By velocity function, the total distance is 8m.
We need to know about velocity to solve this problem. The velocity can be determined as
dV = dX / dT
dX = dV . dT
X = ∫dV . dT
where dV is velocity, dX is distance, dT is the time.
From the question above, we know that:
V(t) = sin(t) m/s
xo = 8 m
to = 0 s
t = 2π s
By substituting the parameters, we can determine the distance
X = ∫dV . dT
Integrate from t = 0 to 2π
X = ∫sin(t) . dT
X = [-cos(t)] + xo
the value of [-cos(t)] + xo from t = 0 to 2π is
X = [-cos(2π) - (-cos(0))] + 8
X = (-1 + 1) + 8
X = 8 m
For more on velocity at: brainly.com/question/25749514
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Answer:
a) 30.58°
b) 367.55 N
Explanation:
Given:
Diameter of the specimen, D = 63mm = 0.063 m
Height of the specimen, H = 25 mm
Shear force at failure, 
Shear stress at failure, 
Area = 
or
Area = 
thus,
Shear stress at failure, 
a) 
............(1)
where,
C' = cohesion
for sand C' = 0
∅' = angle of friction
σ' = Normal stress
on substituting the values we get,
or
or
b) Shear force required at the time of failure with normal stress 200 KN/m² can be calculated by using the equation 1
on substituting the values, we get
or
shear force will be = 118.185 × area
or
shear force will be = 118.185 × 0.00311 = 0.36755 KN = 367.55 KN
