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denpristay [2]
3 years ago
8

Which of the following is an example of a physical change but not a chemical change?

Physics
2 answers:
vazorg [7]3 years ago
7 0

A water pipe freezes and cracks on a cold night. <em> (D)</em>

There are three physical changes going on in this scenario:

1).  The air gets cold and dark at night.

2).  The water in the pipe freezes and expands.

3).  The pipe cracks.

There are no chemical changes in the description.

Radda [10]3 years ago
5 0

Answer:

<u>A water pipe freezes and cracks on a cold night</u>

Explanation:

A water pipe freezing and cracking is a physical change, not a chemical change. A physical change is a change in what the item looks like, feels like, or how the item has a different form. The water pipe freezing is an example of a physical change because the liquid water has turned to frozen water. The frozen water has expanded the pipe, causing it to crack. There are no chemical changes taking place in this scenario.

Mordancy.

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In lightning , light is seen first and sound is heard later it is due to
Maksim231197 [3]

Answer:

option 4

Explanation:

Light's velocity in air ( 3 × 10^8 m/s ) is much greater than sound's velocity in air ( 343 m/s )

Hence due to difference in velocities , during lightning light is seen first & sound is heard later

8 0
3 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Aneli [31]

d^2=4^2+3^2\\\\d^2=16+9\\\\d^2=25\\\\d=5

3 0
3 years ago
The quantum state of a particle can be specified by giving a complete set of quantum numbers (n,l, ml, ms). How many different q
Delvig [45]

Answer:

number of quantum states =  8

Explanation:

To find the total number of allowed states you take into account the following relations:

l=n-1\\\\m_l=-l,-(l-1),...,0,,,,(l-1),l

in this case you have:

n=2\\\\l=0,1\\\\m_0=0\\\\m_1=-1,0,1

furthermore, for each n,l,ml quantum state you have two additional states due to the spin of the electrons.

then, you have (n,l,ml) = (2,0,0), (2,1,-1), (2,1,0), (2,1,1) and with the spin:

number of quantum states = 2*(1+3) = 8

4 0
3 years ago
A stationary 12.5 kg object is located on a table near the surface of the earth. The coefficient of static friction between the
Sophie [7]

When the object is at rest, there is a zero net force due the cancellation of the object's weight <em>w</em> with the normal force <em>n</em> of the table pushing up on the object, so that by Newton's second law,

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0   →   <em>n</em> = <em>w</em> = <em>mg</em> = 112.5 N ≈ 113 N

where <em>m</em> = 12.5 kg and <em>g</em> = 9.80 m/s².

The minimum force <em>F</em> needed to overcome <u>maximum</u> static friction <em>f</em> and get the object moving is

<em>F</em> > <em>f</em> = 0.50 <em>n</em> = 61.25 N ≈ 61.3 N

which means a push of <em>F</em> = 15 N is not enough the get object moving and so it stays at rest in equilibrium. While the push is being done, the net force on the object is still zero, but now the horizontal push and static friction cancel each other.

So:

(a) Your free body diagram should show the object with 4 forces acting on it as described above. You have to draw it to scale, so whatever length you use for the normal force and weight vectors, the length of the push and static friction vectors should be about 61.3/112.5 ≈ 0.545 ≈ 54.5% as long.

(b) Friction has a magnitude of 15 N because it balances the pushing force.

(c) The object is in equilibrium and not moving, so the acceleration is zero.

5 0
3 years ago
And explosion occur 17 km away the time it takes for it sound to reach your ears traveling at 340 m/s is
Mrrafil [7]

Answer:

<h3>t = 100secs</h3>

Explanation:

The following data

Distance x = 17km = 17000m

Speed v = 340m/s

Using the formula to get the time;

2x = vt

t = 2x/v

t = 2(17000)/340

t = 34000/340

t = 100secs

<em>Hence it takes 100seconds for the sound to reach your ears</em>

6 0
2 years ago
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