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aivan3 [116]
3 years ago
13

William B. Hartsfield was a man of humble origins who became one of the greatest mayors of Atlanta. He served as mayor for six t

erms (1937–41, 1942–61), longer than any other person in the city's history. Hartsfield held office during a critical period when the color line separating the races began to change and the city grew . . . to a metropolitan population of one million. He is credited with developing Atlanta into the aviation powerhouse that it is today . . . . . . . On August 30, 1961, the city peacefully integrated its public schools. As a result, Atlanta began to acquire its reputation as "A City Too Busy to Hate."
–New Georgia Encyclopedia

During Hartsfield’s time in office, Atlanta became known as "A City Too Busy to Hate.” What factors supported this nickname? Check all that apply.

The city integrated its schools.
Atlanta became a leader in aviation.
The economy declined.
The population increased to one million.
Many people served as the city mayor.
Physics
2 answers:
Genrish500 [490]3 years ago
6 0

Answer:

bv guy iukl,

Explanation:

sdfghjkljxcvbnjjjjjjj

ki77a [65]3 years ago
3 0
So basically the first answer would be correct, i hope i could help.
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Temperature doesn't really affect solubility on liquids so it can only be D besides it's already a liquid....
5 0
3 years ago
Read 2 more answers
Manufactured bolts can’t be too long or too short or they might not fit where they need to. Help determine which bolts will work
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What is the longest the bolt can be and still be acceptable
5 0
3 years ago
an empty density bottle weighed 23.5 and 48.4g when filled with water .The empty bottle was partially filled with sand until and
gavmur [86]

Answer:

Density of Sand is 2.653g/cm^{3}.

Explanation:

Given Empty Density bottle weighs 23.5gm(W=23.5gm)

Weight of bottle when completely filled water=48.4gm

So amount of water required to fill the bottle=Weight of bottle filled with water-W

Amount of water required to fill the bottle(w_{max})=48.4gm-23.5gm

w_{max}=24.9g

Since we know density of water d_{w} =1g/cm^{3} and w_{max}

We can calculate volume of empty space in the bottle(V).

w_{max}=d_{w}\timesV

V=\frac{w_{max} }{d_{w} }

V=\frac{24.9}{1}

V=24.9 g/cm^{3}

Now bottle is partially filled with sand,and weight of bottle is (w_{s})36.5gm

So,

Amount of sand added (m_{s})=36.5-Weight of the bottle

m_{s}=13g

After filling the bottle with water again,the weight of the bottle becomes (W_{2}=56.5g)

Therefore,

amount of water added to the bottle of sand in grams = W_{2}-36.5gm

amount of water added =56.5g-36.5g

amount of water added =20g

As the density of water = 1g/cm^{3}

Amount of water (in grams )=Volume of water occupied

20=volume of water added

Therfore volume of water added to the sand filled bottle(V_{w})=20cm^{3}

As we know the total volume of the water bottle(V),

Volume of the sand occupied in the water bottle=V-V_{w}

V_{s}=24.9g-20g

V_{s}=4.9g

We know,

Density=Mass/Volume

Therefore,

density of sand = \frac{m_{s} }{V_{s} }

density of sand =\frac{13}{4.9}

density of sand = 2.653g/cm^{3}

8 0
2 years ago
The spring is compressed a total of 3.0 cm, and used to set a 500 gram cart into motion. Find the speed of the cart at the insta
BartSMP [9]

Answer:

1.15 m/s

Explanation:

Part of the question is missing. Found the missing part on google:

"1. A hanging mass of 1500 grams compresses a spring 2.0 cm.   Find the spring constant in N/m."

Solution:

First of all, we need to find the spring constant. We can use Hooke's law:

F=kx

where

F=mg=(1.5 kg)(9.8 m/s^2)=14.7 N is the force applied to the spring (the weight of the hanging mass)

x = 2.0 cm = 0.02 m is the compression of the spring

Solving for k, we find the spring constant:

k=\frac{F}{x}=\frac{14.7}{0.02}=735 N/m

In the second part of the problem, the spring is compressed by

x = 3.0 cm = 0.03 m

So the elastic potential energy of the spring is

U=\frac{1}{2}kx^2=\frac{1}{2}(735)(0.03)^2=0.33 J

This energy is entirely converted into kinetic energy of the cart, which is:

U=K=\frac{1}{2}mv^2

where

m = 500 g = 0.5 kg is the mass of the cart

v is its speed

Solving for v,

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(0.33)}{0.5}}=1.15 m/s

4 0
3 years ago
A tow truck exerts a force of 1850 N on a 840 kg car. What is the acceleration of the car during this time?
Harrizon [31]

Answer:

<h2>2.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{1850}{840}  =  \frac{185}{84} \\   = 2.20238095...

We have the final answer as

<h3>2.2 m/s²</h3>

Hope this helps you

4 0
3 years ago
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