Answer:
1. 0.5
2. 3/4
3. -6
4. 5x
Step-by-step explanation:
1. A coefficient is a number that is placed in front of an algebraic term/variable in an expression or equation.
The decimal coefficient is therefore 0.5. It is the coefficient of x.
2. The fractional coefficient is 3/4. It is the coefficient of y.
3. The negative coefficient is -6. It is the coefficient of b.
4. A like term is one which contains the same type of terms as another term.
3x is a like term of 5x, because it contains a numerical term and an algebraic term to the power of 1.
<em>Answer,</em>
C. 1650
<em>Explanation,</em>
<em>495/6 = 82.5</em>
<em>82.5 x 20 = </em><em>1650</em>
<u><em>Hope this helps :-)</em></u>
3x-5 is a midline of that triangle so:
![3x-5=\dfrac{1}{2}\cdot20\\\\\\3x-5=10\\\\3x=15\quad|:3\\\\\boxed{x=5}](https://tex.z-dn.net/?f=3x-5%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot20%5C%5C%5C%5C%5C%5C3x-5%3D10%5C%5C%5C%5C3x%3D15%5Cquad%7C%3A3%5C%5C%5C%5C%5Cboxed%7Bx%3D5%7D)
Answer D.
The irrational number that can be added to pi to get a rational sum is PI.
Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2