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zubka84 [21]
3 years ago
6

Order the integers from least to greatest {-11,8,-13,-2,16}

Mathematics
1 answer:
Dovator [93]3 years ago
3 0
Least to Greatest going ⬇
-13
-11
-2
8
16
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A basketball is shaped like a sphere as shown in the diagram. The basketball has a radius of 4.7 inches.
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434.9

Step-by-step explanation:

The circumference is 29.53.

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Identify the Vertex: x^2 - 12x + 44
nikklg [1K]

The vertex of the given quadratic polynomial function is (6, 8)

A quadratic polynomial function is the one which can be represented in the form ax² + bx + c = y where a, b and c are coefficients and x, and y are independent and dependent variables respectively. A parabola is formed when the quadratic polynomial is plotted on graph. The x coordinate of the vertex can be found using formula (-b/2a) and y coordinate can be found by putting the value of x in the equation.

Given polynomial function x² - 12x + 44

Now, x = (-b/2a)

x = (12/2)

=> x = 6

Now, y = 6² - 12×6 + 44

y = 36 - 72 + 44

=> y = 8

Therefore, Vertex = (6, 8)

Learn more about Vertex of quadratic polynomial at:

brainly.com/question/15385707

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Infants who weigh less than 2,500 grams (5 1/2 pounds) at birth are called
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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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