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AVprozaik [17]
3 years ago
9

Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3.

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0
The volume at time <span>t = 25 seconds
since </span><span> V = 4 sqrt(t) cm3, 
 V(5)= 4*</span><span>sqrt(25)cm^3=4*5=20cm^3</span>
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ILL MARK BRAINIEST IF YOU CAN DO THIS RIGHT!!!
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y2 - y1                                                             x1  y1          x2  y2

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5 0
3 years ago
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Bogdan [553]

Answer:

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7 0
1 year ago
Read 2 more answers
xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc
leonid [27]

Answer:

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Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

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<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

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