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maria [59]
3 years ago
7

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
erik [133]3 years ago
8 0

Answer:

Grades 6 and 8

Step-by-step explanation:

If the relationship of girls to boys in two different grades are proportional, <u>they must have the same ratio</u>. To tackle this problem, we can find the <u>ratios</u> of genders in each grade and compare them.

Step 1, finding ratios:

Finding ratios is just like <u>simplifying fractions</u>. We will reduce the numbers by their<u> greatest common factors</u>.

  • GRADE 6:

9:12=\\3:4

  • GRADE 7:

12:18=\\2:3

  • GRADE 8:

15:20=\\3:4

  • GRADE 9:

25:36

<u>Can't be simplified!</u>

<u />

Step 2:

Notice how grades 6 and 8 both had a ratio of 3:4. We can conclude that these two grades have a proportional relationship between girls and boys.

<em>I hope this helps! Let me know if you have any questions :)</em>

<u />

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Maya runs a farm stand that sells raspberries and blueberries. Each pound of raspberries sells for $1 and each pound of blueberr
aniked [119]

30 pounds of raspberries and 50 pounds of blueberries are sold

<em><u>Solution:</u></em>

Let "a" be the pounds of raspberries sold

Let "b" be the pounds of blueberries sold

Cost per pound of raspberry = $ 1

Cost per pound of blue berry = $ 3.25

<em><u>Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries</u></em>

Therefore,

a + b = 80

a = 80 - b ------- eqn 1

<em><u>Maya made $192.50. Therefore, frame a equation as:</u></em>

pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50

a \times 1 + b \times 3.25 = 192.50

a + 3.25b = 192.50 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

80 - b + 3.25b = 192.50

2.25b = 192.50 - 80

2.25b = 112.5

Divide both sides by 2.25

b = 50

<em><u>Substitute b = 50 in eqn 1</u></em>

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Thus 30 pounds of raspberries and 50 pounds of blueberries are sold

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natta225 [31]
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