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Hatshy [7]
3 years ago
6

Simplify. I need this answer.. ​

Mathematics
1 answer:
anygoal [31]3 years ago
3 0
Look at the image attacked please :)

Ignore the bit crossed out at the bottom

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Subtract:<br> 7n - (2n-8)<br> Your answer should be in simplest terms.<br> Enter the correct answer
rewona [7]

Answer:

5n+8

Step-by-step explanation:

We are swamped with questions today so i will not be able to provide you with work. But I'm a college professor. Trust my answer.

Glad I was able to help!!

8 0
3 years ago
Read 2 more answers
for some reason brainly deleted this for not being "school related" even though it is so here's a repost, can anyone help me wit
tangare [24]

Answer:

1 tenth and 9 hundreds

Step-by-step explanation:

Ok so this is not a gud explanation but believe me that answer is correct

a tenth is 10% out of a hundred so thats 10/100 and since the 9 hundreds is already there 10/100+ 9/100= 19/100

Hope you have a gud day :)

6 0
2 years ago
Please help me with this homework
Agata [3.3K]

Answer:

-14.2, -7.8, 12.6, 15.3

Step-by-step explanation:

7 0
3 years ago
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.
Oduvanchick [21]

Answer:

11402.66 m^{2}

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by \frac {0.5\pi d^{2}}{4}

Total area of semi circle will be 2\times\frac {0.5\pi d^{2}}{4}

Substituting 74 m for d and \pi as 3.14 we obtain

Total area semi-circle=2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}

Area of rectangle is given by the product of length and width

Rectangular area=96 m*74 m=7104 m^{2}

Total area of rectangular and semi-circles will be

4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}

Therefore, area of training field is 11402.66 m^{2}

6 0
3 years ago
The owner of a local nightclub has recently surveyed a random sample of n = 300 customers of the club. She would now like to det
quester [9]

Answer:

We cannot determine the appropriate hypotheses to test this study because we are only given the data for the sample size and the population mean. Meanwhile, we need to know the data of the sample mean, the standard deviation and the level of significance before we can state the appropriate hypotheses for this test.

Step-by-step explanation:

Given that:

sample size n = 300

population mean μ = 35

The null hypothesis and the alternative hypothesis can be computed as follows:

Null hypothesis

H_o: \leq  35

Alternative hypothesis

H_1 > 35

The degree of freedom df = n -1

df = 300 - 1

df = 299

8 0
3 years ago
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