Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.
Therefore, amount of the material left after 10 days would be 0.5 kg.
Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:-5
Step-by-step explanation:
i could be wrong i used my calculator
Answer:
an = 1/2 (n) (n+1)
Step-by-step explanation:
1,3,6,10,.........
3-1=2
6-3=3
Each term is different so there is no common difference. It is not an arithmetic sequence
3/1=3
6/3 =2
Each term is different so there is no common ratio. It is not a geometric sequence
1 3 6 10
+2 +3 +4
a1 = 1
a2 = 3
a3 = 6 = 2*3
a4 = 10 = 2*5
Answer:
(x, y) → (kx, ky)
Step-by-step explanation:
Answer:
-8
Step-by-step explanation:
Create this equation into a y=mx+b form
8x-3y=24
-8x -8x -8 to solve for -3y
-3y=-8x+24
---- --- --- divide by -3 to leave y by itself
-3 -3 -3
y= 8
--- x-8
3
y intercept is -8
