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Sladkaya [172]
3 years ago
8

How many solutions 2x+3y=-3 and 3x + 5y = -9

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0
Since the slopes of the two lines are the not equal, they will have only one solution. The solution will be a point and can be found using the method given below.

We can find the solutions by simultaneously solving the two equations.

From first equation, the value of y comes out to be:

2x+3y=-3 \\  \\ 
3y=-3-2x \\  \\ 
y= \frac{-3-2x}{3}

Using this value of y in second equation, we get:

3x+5( \frac{-3-2x}{3} )=-9 \\  \\ 
9x-15-10x=-27 \\  \\ 
-x=-27+15 \\  \\ 
-x=-12 \\  \\ 
x=12

Using this value of x, we can find y:

y= \frac{-3-2x}{3}= \frac{-3-24}{3} =-9

Therefore, there is only one solution to the given equations is which is (12, -9)
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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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The absolute value of x is never negative, so given the absolute value of x we can't determinate if x was positive or negative (if x =/ 0) before the absolute value was taken.

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Answer:

10xline y=46

Step-by-step explanation:

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