Eight times the result of subtracting 3 from a number is equal to the number increased by 25. What is the number?

Consider this system of equation. Which shows the second equation written in slope-intercept form?y = 3x - 210(x+3/5)=2yA) y=5x+

SashulF [63]

we have that

y = 3x - 2

10(x+3/5)=2y------> the second equation----->divide by 2 both sides

5(x+3/5)=y-----> y=5x+3

y=5x+3------> second equation written in slope-intercept form

so

case A) y=5x+3/10-----> is not equal to y=5x+3

case B) y=5x+3--->is equal to y=5x+3---------> is the answer

case C) y=1/5x+3/25-------> is not equal to y=5x+3

case D) y=1/2x+6-----> is not equal to y=5x+3

therefore

the answer is the option

B) y=5x+3

7 0

3 years ago

Hello! It would help a lot if I had assistance with this question:

Reika [66]

It's an irrational number.

You can cross off terminating and repeating decimal so you're left with a rational or irrational number. A rational number is something that can be put into fraction form and/or have repeating or terminating decimals.

So our answer would be irrational.

7 0

3 years ago

Read 2 more answers

Apply Newton’s method to estimate the solution of x3 − x − 1 = 0 by taking x1 = 1 and finding the least n such that xn and xn +

ss7ja [257]

Solution :

Given

$f(x)=x^3-x-1, x_1=1$

$f'(x)=3x^2-1$

Let the initial approximation is $x_1 =1$

So by Newton's method, we get

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)},n=1,2,...$

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}=1-\frac{1^3-1-1}{3(1)^2-1}=1.5$

$x_3=1.5-\frac{(1.5)^3-1.5-1}{3(1.5)^2-1}=1.34782608$

$x_4=1.34782608-\frac{(1.34782608)^3-1.34782608-1}{3(1.34782608)^2-1}=1.32520039$

$x_5=1.32520039-\frac{(1.32520039)^3-1.32520039-1}{3(1.32520039)^2-1}=1.32471817$

$x_6=1.32471817-\frac{(1.32471817)^3-1.32471817-1}{3(1.32471817)^2-1}=1.32471795$

$x_5 \approx x_6$ are identical up to eight decimal places.

The approximate real root is x ≈ 1.32471795

∴ x = 1.32471795

4 0

3 years ago

Can anyone help me plz?

Nat2105 [25]

<h3>Answer: Third choice. $\overline{AC} \perp \overline{BD}$ </h3>

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Explanation:

SAS stands for Side Angle Side. Note how the angle is between the two sides. To prove the triangles congruent with SAS, we need to know two sides and an angle between them.

We already see that BC = CD as shown by the tickmarks. Another pair of sides is AC = AC through the reflexive theorem.

The missing info is the angle measures of ACB and ACD. If we knew those angles were the same, then we could use SAS to prove triangle ACB is congruent to triangle ACD.

It turns out that the angles are congruent only when they are 90 degrees each, leading to AC being perpendicular to BD. We write this as $\overline{AC} \perp \overline {BD}$ . The upside down T symbol meaning "perpendicular" or "the two segments form a right angle".

4 0

3 years ago

HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.

MAXImum [283]

Answer:

$\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}$

Step-by-step explanation:

$a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100$

4 0

3 years ago